I agree to Careers360’s Privacy Policy and Terms & Conditions and provide consent to be contacted for promotion via mail, sms, whatsapp, etc.
With the CSAB College Predictor 2025 tailored especially for candidates in future admission forecasting by Careers360's tool future hopefuls can determine their odds based on their JEE (Main) performance and historic cutoffs. The simple predictor helps students make good decisions and reveals schools that match their academic suitability. Through its use of historical data and trends, the tool increases candidates' likelihood of achieving admission to their favoured institutions. Special rounds for empty and supernumerary seats allow the CSAB College Predictor to deliver enhanced options for gaining quality education throughout various technical institutions in India.
The CSAB College Predictor 2025 helps students predict potential colleges where they might be eligible to take admission on the basis of their ranks in JEE (Main). Showing colleges, vacant seats and cost of fees helps with the admission. Cutoff trends, along with historical data, aid in making smart decisions, and improve your chances of being accepted into a specific claimed institution.
Using the CSAB Counselling College predictor tool of 2025 is very simple. Candidates need to follow these steps to predict the colleges they may be eligible for:
Go to the Careers360 website and take a look at 2025 College Predictor.
Please complete the fields JEE Main percentile and other specification details here.
Navigate to the “Predict My Colleges” tab or push the button with the corresponding name.
Depending on the percentile and other requirements the CSAB Counselling College Predictor 2025 tool will present a list of colleges to the candidate.
With the CSAB Counselling College Predictor 2025 available from Careers360 comes a range of perks. By sorting colleges based on ranks and categories it assists students in selecting colleges better and consolidating the counselling steps. Using categories and ranks from JEE Main allows the tool to present different colleges and broadens the opportunity for colleges of choice.
What do you get with the CSAB College Predictor 2025 tool by Careers360?
By using the CSAB Counselling college predictor tool 2024 created by Careers360 a candidate can find eligible colleges according to their JEE Main rankings and additional qualifications.
It forms a panel of good institutions by combining the information from earlier tests and the cutoff percentages for interest.
The tool will help the candidates to make their college decisions and organise their counselling schedule.
It gathers information about colleges’ ranks, eligibility criteria, placements, and tuition fees.
For the complete details of the best CSAB colleges in the table below:
S.No
CSAB Participating Institutions
1
Siksha 'O' Anusandhan, Bhubaneswar
2
KIIT University - Kalinga Institute of Industrial Technology
3
NIT Rourkela - National Institute of Technology Rourkela
4
IIT Bhubaneswar - Indian Institute of Technology
5
C.V. Raman Global University, Odisha
6
Veer Surendra Sai University of Technology
7
Silicon Institute of Technology (SIT), Bhubaneswar
A score of 32 in JEE Main generally corresponds to a percentile range of about 50 to 60, making it difficult for general category students to secure admission to NITs or IIITs, but you still have good chances in GFTIs and state colleges, especially with the Home State quota, OBC/SC/ST/EWS,
JEE Mains 2026 result for session 1 will be declared by February 12. For more details check
https://engineering.careers360.com/articles/jee-main-result
Below are the day-wise JEE Main session 1 questions and answers
https://engineering.careers360.com/download/ebooks/jee-main-2026-analysis-january-session
The complete analysis for JEE Main Jan 29 shift 1 exam 2026 will be updated soon at https://engineering.careers360.com/articles/jee-main-2026-january-29-question-paper-with-solutions-pdf
JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-
https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-2-question-paper-with-solutions-pdf
The JEE Main Jan 28 paper for shift 1 was moderate. Although Chemistry was a bit tricky. As expected, Maths was time consuming. But Physics was on the easier side.
You can find the answers for Jan 28 shift 1 online. They are memory based. I found this article helpful
Hi Lucky, Please refer to this link and you can download the free pdf.
https://engineering.careers360.com/download/ebooks/jee-main-2026-memory-based-questions-and-analysis-of-21st-january-shift-1
625 = ms Δ T + mL 625 = m [ 125 × 300 + 2.5 × 10 4 ] 625 = m [ 37500 + 25000 ] 625 = m [ 62500 ] m = 1 100 kg M = 10 grams
HI Manisha Maharana
You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf. https://engineering.careers360.com/download/sample-papers/jee-main-10-full-mock-test-and-explanations-pdf Also, you can check ad attemp the online mock test on our platform. https://learn.careers360.com/test-series-jee-main-free-mock-test/
A general equation of a circle is
$ x^2+y^2+2 g x+2 f y+c=0 $
Since it passes through $(0,0)$,
$ c=0 $
So the equation becomes
$ x^2+y^2+2 g x+2 f y=0 $
It cuts the x -axis at ( $a, 0$ ).
Substituting:
$ a^2+2 g a=0 $
g=-a/2
Feb. 2, 2026, 2:56 p.m. IST
Feb. 1, 2026, 10:32 p.m. IST
Feb. 1, 2026, 3:48 p.m. IST
Jan. 31, 2026, 5:58 p.m. IST
Jan. 31, 2026, 4:02 p.m. IST
Jan. 29, 2026, 11:01 p.m. IST
Jan. 29, 2026, 3:12 p.m. IST
Jan. 29, 2026, 9:17 a.m. IST
Jan. 28, 2026, 9:18 p.m. IST
Jan. 28, 2026, 7:16 p.m. IST
You have utilised this predictor with several unique . To continue, use one of the you have used before or get your limit reset by following options.
In case of any query/clarification, reach out to us at 0124-4444360 or info@careers360.com
And never miss an important update
