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List of Engineering colleges accepting 98 Percentile in JEE Main 2024

List of Engineering colleges accepting 98 Percentile in JEE Main 2024

Edited By Team Careers360 | Updated on Jun 26, 2024 02:31 PM IST | #JEE Main

List of Engineering Colleges Accepting 98 Percentile in JEE Main 2024: The scoring percentile of 98 in the Joint Entrance Examination (JEE) Main is a big achievement, which opens the door to admission for many esteemed engineering institutions across India. Finding the right college is always difficult, but students should research properly. According to the below list, most students have chosen B.Tech Computer Science and engineering as their preferred course.

List of Engineering colleges accepting 98 Percentile in JEE Main 2024
List of Engineering colleges accepting 98 Percentile in JEE Main 2024

Students had chosen the Indian Institute of Information Technology as their most preferred. The National Institute of Technology came in at a close second as the preferred institution to pursue their desired courses. In this article, students can check the institution's best courses along with their opening-closing ranks.

List of Engineering Colleges Accepting 98 Percentile in JEE Main 2024

In the below list, we have shortlisted the institutions with their institute names and what their cutoff scores are, along with their opening rank and closing rank. This will give you a brief understanding of the college.

List of Colleges Accepting 98 JEE Main Percentile for B.Tech

College Name

Best Course Name

Best Course cutoff

Opening Rank

Closing Rank




Gender-Neutral

Female only

Gender-Neutral

Female only

Indian Institute of Information Technology, Pune

B.Tech Computer Science and Engineering

98.65573844

4202

8290

14966

21049

Indian Institute of Information Technology, Vadodara

B.Tech Computer Science and Engineering

98.37019738

8180

14659

18145

23183

Indian Institute of Information Technology, Sonipat

B.Tech Computer Science and Engineering

98.15732154

13718


20515


Indian Institute of Information Technology, Kota

B.Tech Computer Science Engineering

98.2758853

12721

18761

19195

25937

Indian Institute of Information Technology, Guwahati

B.Tech Computer Science Engineering

98.3822334

4747

20043

18011

25231

Indian Institute of Information Technology, Surat

B.Tech Computer Science and Engineering

98.35501763

13182

21205

18314

23255

Dr Shyama Prasad Mukherjee International Institute of Information Technology, Naya Raipur

B.Tech Computer Science and Engineering

98.46783284





Indian Institute of Information Technology, Bhopal

B.Tech Computer Science and Engineering

98.04854827

9034


21726


Indian Institute of Information Technology, Nagpur

B.Tech Computer Science Engineering Artificial intelligence and Machine Learning

98.10747086

10066


21070


Indian Institute of Information Technology Tiruchirappalli

B.Tech Computer Science and Engineering

98.03579368

5847

10606

21868

29245

Indian Institute of Information Technology Design and Manufacturing Kancheepuram

B.Tech Computer Engineering

98.68816383

10441

11974

14605

18196

Indian Institute of Information Technology Design and Manufacturing Jabalpur

B.Tech Computer Science and Engineering

98.82334449

8582

14277

13100

20311

National Institute of Technology Patna

B.Tech Computer Science and Engineering

98.6606786

10277

19270

14911

23590

National Institute of Technology Andhra Pradesh

B.Tech Computer Science and Engineering

98.65807379

9262

12616

14940

19909

National Institute of Technology Durgapur

B.Tech Computer Science and Engineering

98.9904116

3070

2136

11240

13052

National Institute of Technology Silchar

B.Tech Computer Science and Engineering

98.05241057

8643

19002

21683

26643

Dr B R Ambedkar National Institute of Technology Jalandhar

B.Tech Computer Science and Engineering

98.73729594

8346

5952

14058

16727

Punjab Engineering College, Chandigarh

BE Computer Science and Engineering

98.61981003

3290


15366


National Institute of Technology Raipur

B.Tech Computer Science Engineering

98.22612445

10067

15044

19749

20935

National Institute of Technology Hamirpur

B.Tech Computer Science and Engineering

98.21938787

9578

22031

19824

32375

National Institute of Technology Goa

B.Tech Computer Science and Engineering

98.40765275

8059

21386

17728

21386

The National Institute of Technology, Durgapur, has the highest cutoff score of 98.9904116 percentile, while the lowest cutoff score belongs to the Indian Institute of Information Technology, Tiruchirappalli, with a score of 98.03579368.

Marks for 98 percentile in JEE mains 2024

To score 98 percentile in the JEE Mains 2024 exam, candidates are required to score a minimum of 149 marks out of 300 in the exam. This score is based on the percentile comparison released by NTA on the official website.

Candidates can check the percentile conversions for various scores from the table below

Expected JEE Main 2024 Marks vs Rank vs Percentile

Marks out of 300

Rank

Percentile

286- 292

19-12

99.99826992- 99.99890732

280-284

42-23

99.99617561 - 99.99790569

268- 279

106-64

99.99034797 - 99.99417236

250- 267

524-108

99.95228621- 99.99016586

231-249

1385-546

99.87388626-99.95028296

215-230

2798-1421

99.74522293-99.87060821

200-214

4667-2863

99.57503767- 99.73930423

189-199

6664- 4830

99.39319714- 99.56019541

175-188

10746-7152

99.02150308 - 99.3487614

160-174

16163-11018

98.52824811-98.99673561

149-159

21145-16495

98.07460288-98.49801724

132-148

32826-22238

97.0109678-97.97507774

120-131

43174-33636

96.0687115-96.93721175

110-119

54293-44115

95.05625037-95.983027

102-109

65758-55269

94.01228357-94.96737888

95-101

76260-66999

93.05600452 -93.89928202

89-94

87219-78111

92.05811248 -92.88745828

79-88

109329-90144

90.0448455 -91.79177119

62-87

169542-92303

84.56203931-91.59517945

41-61

326517-173239

70.26839007-84.22540213

1-40

1025009-334080

6.66590786-69.5797271

Frequently Asked Questions (FAQs)

1. Which colleges accept the 98 percentile?

There are many colleges to choose from if you have obtained 98 percentile in the JEE Main exam some of them are NIT Raipur, NIT Hamirpur, NIT Goa,

2. What are the best colleges for the 98 percentile?

Many best colleges accept the 98 percentile. IIITs and NITs also accept 98 percentile. Many colleges accept the 98 percentile including IIITs and NITs. 

3. Which NIT is best for the 98 percentile?

Some of the best NITs that accept the 98 percentile are NIT Raipur, NIT Hamirpur, NIT Goa, NIT Andhra Pradesh etc.,

4. What are the marks for the 98 percentile in JEE Main?

It is very difficult to predict the marks as it keeps changing every year depending on various factors such as the number of students who appear in the exam and the toughness level of the examination.

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Questions related to JEE Main

Have a question related to JEE Main ?

Newton's Laws of Motion are fundamental to understanding the motion of objects. Here are the key formulas and concepts for JEE Mains:

Newton's First Law of Motion (Law of Inertia):

  • An object at rest will remain at rest, and an object in motion will continue to move in a straight line with constant speed, unless acted upon by an unbalanced force.

Newton's Second Law of Motion:

  • The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

  • Formula: F = ma
    • F: Net force (N)
    • m: Mass of the object (kg)
    • a: Acceleration of the object (m/s²)


    Newton's Third Law of Motion (Law of Action and Reaction):

    • For every action, there is an equal and opposite reaction.


    Important Formulas and Concepts:

    • Weight: W = mg
      • W: Weight of the object (N)
      • m: Mass of the object (kg)
      • g: Acceleration due to gravity (9.8 m/s²)
    • Friction: The force that opposes the relative motion between two surfaces in contact.
      • Static friction: Fs ≤ μsN
      • Kinetic friction: Fk = μkN
        • μs: Coefficient of static friction
        • μk: Coefficient of kinetic friction
        • N: Normal force
    • Tension: The force transmitted through a string, rope, or cable when it is pulled taut.
    • Normal force: The force exerted by a surface on an object in contact with it, perpendicular to the surface.
    • Centripetal force: The force that causes an object to move in a circular path.
      • Fc = mv²/r
        • Fc: Centripetal force (N)
        • m: Mass of the object (kg)
        • v: Velocity of the object (m/s)
        • r: Radius of the circular path (m)


    These formulas and concepts are essential for understanding Newton's Laws of Motion and solving problems related to mechanics in JEE Mains. Practice solving a variety of problems to solidify your understanding and improve your problem-solving skills.


    I hope it helps !!

Hello aspirant,

Here's a breakdown of your options and factors to consider:

Option 1: Continue with Sachin Rana's videos

Advantages:

  • Familiarity: You're already comfortable with his teaching style and approach.
  • Progress: You've made progress in GOC and isomerism, building a foundation.
  • Time Efficiency: You might be able to complete the remaining chapters faster since you've already covered some basics.

Disadvantages:

  • Uncertain Completion Time: Completing all of NS sir's lectures might take longer than you anticipate, potentially affecting your preparation for the JEE Advanced.
  • Lack of Focus: You might find it difficult to switch between two different teaching styles and approaches.

Option 2: Switch to NS sir's lectures

Advantages:

  • Comprehensive Coverage: NS sir's lectures are known for their depth and clarity, ensuring a thorough understanding of all organic concepts.
  • Advanced Preparation: Focusing on NS sir's lectures could help you prepare better for the JEE Advanced level.

Disadvantages:

  • Restarting from GOC: You'll need to revisit some concepts you've already covered with Sachin Rana.
  • Time Investment: Completing all of NS sir's lectures might take longer than you currently have.

Decision-Making Factors:

  1. Your Current Progress: If you feel confident with your understanding of GOC and isomerism from Sachin Rana, you can consider continuing with him. However, if you want a more comprehensive and in-depth understanding, switching to NS sir might be beneficial.
  2. Time Constraints: Assess how much time you have before the JEE Advanced. If time is a major factor, sticking with Sachin Rana's shorter videos might be more efficient.
  3. Learning Style: Consider which teacher's teaching style resonates better with you. If you prefer a more structured and detailed approach, NS sir might be a good fit.

Recommendation:

Ultimately, the decision should be based on your individual preferences, learning style, and time constraints. It might be helpful to watch a few lectures from both teachers to see which one aligns better with your learning needs.

Additional Tips:

  • Supplement with Practice: Regardless of which teacher you choose, practice regularly to solidify your understanding and problem-solving skills.
  • Mock Tests: Take mock tests frequently to assess your progress and identify areas where you need to improve.
  • Seek Clarification: Don't hesitate to ask questions or seek clarification from your teachers or classmates if you have any doubts.

I hope this guidance helps you make an informed decision!

The five-year combined B.Tech-M.Tech degree in Computer Science & Engineering (Cyber Security) is offered by the National Forensic Sciences University (NFSU) in Delhi. With topics like secure programming, network security, malware analysis, IoT security, and forensics, the curriculum offers an in-depth concentration on computer science, cybersecurity, and digital forensics.

In terms of cut-offs, NFSU bases its admissions decisions on the B.Tech program's JEE Mains rank. Because of the specialised nature of the program, competitive ranks for B.Tech-M.Tech in Cyber Security often fall within upper JEE Main rank bands. However, the actual cut-off for the Delhi campus changes based on criteria including category and seat availability.

There are 40 seats available for the Delhi campus, with reservations for members of the SC, ST, OBC, and EWS groups. For the first three years of the program, the tuition costs are approximately Rs65,000 each semester; after that, they rise to Rs 90,000 per semester.

Atleast you decide to prepare for boards finally no matter how late Just keep the same enthusiasm and zeal for the next three months and you will definitely achieve your goal.

Evaluate the options you have.


Select the best one.


Make a plan for each subject


Go with it till the end no matter how tough the situation is.

Completing organic chemistry (OC) from the Samarpan batch of MKA Sir on YouTube can be a good option for you, especially if you have already covered the basics of GOC and Isomerism. However, there are a few things to consider:

  • Scope of the batch: While the Samarpan batch covers most of the important topics in organic chemistry, it may not go into as much depth as a traditional classroom course. You may need to supplement your learning with additional resources, such as textbooks or online tutorials.
  • Your current level of understanding: If you have a strong foundation in GOC and Isomerism, you may be able to complete the batch relatively quickly. However, if you are struggling with these topics, it may take you longer.
  • Your learning style: If you are a self-directed learner who can work independently, you may be able to benefit from the flexibility and convenience of online learning. However, if you prefer a more structured learning environment, you may find it challenging to stay on track without a teacher or classmates.

Overall, completing organic chemistry from the Samarpan batch of MKA Sir on YouTube is a feasible option for class 12th JEE aspirants. However, it is important to be realistic about your expectations and to supplement your learning with additional resources as needed.


I hope this information helps you.






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