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    Cramer’s Rule - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Cramer’s law is considered one the most difficult concept.

    • 67 Questions around this concept.

    Solve by difficulty

    The number of values of k, for which the system of equations :

    (k+1)x+8y=4k

    kx+(k+3)y=3k-1

    has no solution, is:

    Consider the system of linear equations

    x_{1}+2x_{2}+x_{3}=3

    2x_{1}+3x_{2}+x_{3}=3

    3x_{1}+5x_{2}+2x_{3}=1

    The system has

    If the system of linear equations
    x+ay+z=3
    x+2y+2z=6
    x+5y+3z=b
    has no solution, then :

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    The system of linear equations

    x +λy −z = 0
    λx − y − z = 0
    x + y − λz = 0

    has a non-trivial solution for:

    The set of all values of \lambda for which the system of linear equations :

    2x_{1}-2x_{2}+x_{3}=\lambda x_{1}

    2x_{1}-3x_{2}+2x_{3}=\lambda x_{2}

    -x_{1}+2x_{2}\; \; \; =\lambda x_{3}

    has a non-trivial solution,

    If S is the set of distinct values of ‘b’ for which the following system of linear equations

    x+y+z=1

    x+ay+z=1

    ax+by+z=0

    has no solution, then S is:

    Find the value of p and q such that the system of linear equation has no solution.

    $x+y+z=6, x+2 y+3 z=12, x+2 y+p z=q$

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    Find the value of $x, y \& z$ of system of equation

    $
    x+y+z=9 ; 2 x+5 y+7 z=26 ; 2 x+y+z=0
    $

     

    Concepts Covered - 1

    Cramer’s law

    Cramer’s law

    For the system of equations in two variables:

    Let $a_1 x+b_1 y=c_1$ and $a_2 x+b_2 y=c_2$, where

    $
    \frac{\mathrm{a}_1}{\mathrm{a}_2} \neq \frac{\mathrm{b}_1}{\mathrm{~b}_2}
    $
    On solving this equation by cross multiplication, we get

    $
    \begin{aligned}
    & \frac{x}{b_2 c_1-b_1 c_2}=\frac{y}{a_1 c_2-a_2 c_1}=\frac{1}{a_1 b_2-a_2 b_1} \\
    & \text { or } \frac{\mathrm{x}}{\left|\begin{array}{ll}
    c_1 & b_1 \\
    c_2 & b_2
    \end{array}\right|}=\frac{\mathrm{y}}{\left|\begin{array}{ll}
    a_1 & c_1 \\
    a_2 & c_2
    \end{array}\right|}=\frac{1}{\left|\begin{array}{ll}
    a_1 & b_1 \\
    a_2 & b_2
    \end{array}\right|} \\
    & \text { or } \mathrm{x}=\frac{\left|\begin{array}{ll}
    c_1 & b_1 \\
    c_2 & b_2
    \end{array}\right|}{\left|\begin{array}{ll}
    a_1 & b_1 \\
    a_2 & b_2
    \end{array}\right|}, \mathrm{y}=\frac{\left|\begin{array}{ll}
    a_1 & c_1 \\
    a_2 & c_2
    \end{array}\right|}{\left|\begin{array}{ll}
    a_1 & b_1 \\
    a_2 & b_2
    \end{array}\right|}
    \end{aligned}
    $

    We can observe that the first column in the numerator of x is of constants and 2nd column in the numerator of y is of constants, and the denominator is of the coefficient of variables.

    We can follow this analogy for the system of equations of 3 variables where the third column in the numerator of the value of z will be constant and the denominator will be formed by the value of coefficients of the variables.

    For the system of equations in three variables:

    Let us consider the system of equations

    $
    \begin{aligned}
    & \mathrm{a}_1 \mathrm{x}+\mathrm{b}_1 \mathrm{y}+\mathrm{c}_1 \mathrm{z}=\mathrm{d}_1 \\
    & \mathrm{a}_2 \mathrm{x}+\mathrm{b}_2 \mathrm{y}+\mathrm{c}_2 \mathrm{z}=\mathrm{d}_2 \\
    & \mathrm{a}_3 \mathrm{x}+\mathrm{b}_3 \mathrm{y}+\mathrm{c}_3 \mathrm{z}=\mathrm{d}_3
    \end{aligned}
    $

    then $\Delta$, which will be determinant of coefficient of variables, will be

    $
    \Delta=\left|\begin{array}{lll}
    a_1 & b_1 & c_1 \\
    a_2 & b_2 & c_2 \\
    a_3 & b_3 & c_3
    \end{array}\right|
    $

    $\Delta_1$ numerator of $x$ is :
    $\Delta_1=\left|\begin{array}{lll}d_1 & b_1 & c_1 \\ d_2 & b_2 & c_2 \\ d_3 & b_3 & c_3\end{array}\right|$
    Similarly $\Delta_2=\left|\begin{array}{lll}a_1 & d_1 & c_1 \\ a_2 & d_2 & c_2 \\ a_3 & d_3 & c_3\end{array}\right|$ and $\Delta_3=\left|\begin{array}{lll}a_1 & b_1 & d_1 \\ a_2 & b_2 & d_2 \\ a_3 & b_3 & d_3\end{array}\right|$
    i) If $\Delta \neq 0$, then the system of equations has a unique finite solution and so equations are consistent, and solutions are $\mathrm{x}=\frac{\Delta_1}{\Delta}, \mathrm{y}=\frac{\Delta_2}{\Delta}, \mathrm{z}=\frac{\Delta_3}{\Delta}$
    ii) If $\Delta=0$, and any of $\Delta_1 \neq 0$ or $\Delta_2 \neq 0$ or $\Delta_3 \neq 0$

    Then the system of equations is inconsistent and hence no solution exists.
    iii) If all $\Delta=\Delta_1=\Delta_2=\Delta_3=0$ then

    System of equations is consistent and it has an infinite number of solutions (except when all three equations represent parallel planes, in which case there is no solution)

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    Cramer’s law

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