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Centripetal Force And Centrifugal Force - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Centripetal Force and Centrifugal Force is considered one of the most asked concept.

  • 40 Questions around this concept.

Solve by difficulty

A car of mass 1000kg takes a round turn of radius 50m with a velocity of 36km/h. The centripetal force (in newtons) is:

 

An annular ring with inner and outer radii  R1 and R2 is rolling without slipping with a uniform angular speed. The ratio of the forces experienced by the two particles situated on the inner and outer parts of the ring,F1/Fis,

Two cars of masses m1 and m2 are moving in circles of radii r1 and r2 respectively. Their speeds are such that they make complete circles in the same time t. The ratio of their centripetal acceleration is:

A vehicle of mass 5000 Kg starts taking a circular turn of radius 10 m. The initial speed of the vehicle on a circular track is 5 $\mathrm{m} / \mathrm{s}$ and it is increasing with the rate of $1 \mathrm{~m} / \mathrm{s}^2$. After how much time the vehicle will be just about to overturn [Assume distance between two vehicle $=4 \mathrm{~m}$, the height of the center of mass of vehicle $=2 \mathrm{~m}, \mathrm{~g}=10 \mathrm{~m} / \mathrm{s}^2$ ]

A car starts moving in a circular path with a radius of 200 m. Its speed is increasing at the rate of $2 \mathrm{~m} / \mathrm{s}^2$. The acceleration of the car after 20 seconds of starting motion is 

A particle is going from point A to B in a circular path. The ratio of distance and displacement is

 .

A stone with a mass of  150\ g rotates around a horizontal circle at a speed of 10\ \frac{m}{s} and a attached to the end of a rope   1m long. What is the centripetal acceleration of the stone?

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A stone of mass 1 kg is tied to end of a massless string of length 1 m. If the breaking tension of the string is 400 N, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is :

An electric field due to a positively charged long straight wire at a distance $r$ from its is proportional to $r^{-1}$ in magnitude. Two electrons are orbiting such a long straight wire in circular orbits of radii $1 A$ and $2 A$ The ratio of their respective time period is:

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A car goes around a uniform circular track of radius $R$ at a uniform speed once in every $T$ seconds. The magnitude of the centripetal acceleration is $a_c$. If the car now goes uniformly around a larger circular track of radius $2 R$ and experiences a centripetal acceleration of magnitude $ a_c$, then its time period is:

Concepts Covered - 1

Centripetal Force and Centrifugal Force
  1. Centripetal Force-

  • Force acts on the body along the radius and towards the center.

    

$
\begin{aligned}
& F=4 m \pi^2 n^2 r \\
& F=\frac{4 m \pi^2 n^2 r}{T^2}
\end{aligned}
$


Where
$\mathrm{F}=$ Centripetal force
$\omega=$ Angular velocity
$\mathrm{n}=$ frequency

  1. Centrifugal Force  

  • It is a fictitious force which has significance only in the rotating frame of reference.

  • It is an Imaginary force due to incorporated effects of inertia.

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Centripetal Force and Centrifugal Force

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Centripetal Force and Centrifugal Force

Physics Part II Textbook for Class XI

Page No. : 103

Line : 21

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