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JEE Advanced Sample Papers 2 (Paper 1 & 2) by FIITJEE

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JEE Advanced Sample Papers 2 (Paper 1 & 2) by FIITJEE is a compilation of type of questions that are expected to come in JEE Advanced entrance exam. Download these model question papers and raise your efficiency of solving the questions (expected to come in the actual test of JEE Advanced) to new levels.
JEE Advanced 2025 Sample Papers
Solving the JEE Advanced paper's will help to know the exam difficult level and identify the high weightage topics.
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QnA related to JEE Advanced

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The cutoff ranks for Scheduled Tribe (ST) candidates seeking admission to the B.Tech Civil Engineering program through JEE Advanced vary annually and across different Indian Institutes of Technology (IITs). These variations depend on factors such as the number of applicants, seat availability, and overall performance in the examination. Below is a summary of the closing ranks for ST candidates in B.Tech Civil Engineering at select IITs based on the most recent data:

IIT Closing Rank (ST Category)
IIT Delhi 214
IIT Bombay 335
IIT Roorkee 422
IIT Kharagpur 527
IIT Madras 488
IIT Kanpur 503
IIT Guwahati 585
IIT Hyderabad 612
IIT Gandhinagar 694
IIT Indore 684

Note: These ranks are indicative and pertain to the most recent admission cycle. Actual cutoffs may vary each year.

For the most accurate and up-to-date information, it's advisable to consult the official Joint Seat Allocation Authority (JoSAA) website or the respective IITs' official portals. Cutoff ranks are subject to change annually based on various factors, so staying informed through official channels is essential.

Hello there,

With 92.103 percentile in JEE Mains 2025, your chances of qualifying for JEE Advanced (General category) depend on the official cutoff, which varies yearly.

In recent years, the General category cutoff for JEE Advanced has been around 89-91 percentile. Since your percentile is slightly above this range, you have a good chance of qualifying, but you should wait for the official cutoff announcement by NTA.

I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

Thank you and wishing you all the best for your bright future.

IIT Hyderabad is a premier engineering institution in India, known for its academic excellence, research opportunities, and state-of-the-art infrastructure.


IIT Hyderabad: JEE Advanced Cutoff

To get an idea of the competitiveness, here are the JEE Advanced cutoffs for IIT Hyderabad:


- General Category: Around 500-700 (out of 3600)

- OBC-NCL Category: Around 450-650

- SC Category: Around 350-550

- ST Category: Around 300-500

Here are some reasons why IIT Hyderabad stands out:


1. Research Opportunities: IIT Hyderabad is known for its research focus, with many faculty members and students involved in cutting-edge projects.

2. Interdisciplinary Programs: The institute offers several interdisciplinary programs, such as the B.Tech. in Computer Science and Engineering with a specialization in Artificial Intelligence.

3. Industry Collaborations: IIT Hyderabad has strong industry connections, with many top companies visiting the campus for recruitment.

4. Location: Hyderabad is a hub for the IT and technology industry, providing students with ample opportunities for internships, projects, and placements.


Other Options in Hyderabad

If you're looking for other options in Hyderabad, here are a few:


1. IIIT Hyderabad: A premier institution for IT and computer science education.

2. BITS Pilani, Hyderabad Campus: A renowned private university with a strong focus on engineering and technology.

3. JNTUH: A public university with a strong reputation for engineering and technology education.


Ultimately, the choice depends on your individual preferences, academic goals, and career aspirations.

Hello,

With a 94.357 percentile in JEE Advanced Session I, your estimated rank is approximately between 60,000 to 70,000.

Admission to Computer Science programs in top IITs is highly competitive, typically requiring ranks within the top 500 to 1,000. However, you may consider the following options:

  • Newer IITs : Institutes like IIT Bhilai, IIT Goa, and IIT Jammu may have higher closing ranks for Computer Science, increasing your chances of admission.

  • NITs and IIITs : With your rank, you might secure a seat in Computer Science at certain National Institutes of Technology (NITs) and Indian Institutes of Information Technology (IIITs), especially in newer or less sought-after campuses.

  • State Engineering Colleges : Consider reputable state engineering colleges where your JEE Advanced rank may meet the Computer Science admission criteria.

It's advisable to participate in the Joint Seat Allocation Authority (JoSAA) counseling process to explore available options based on your rank.

You can also use the JEE Advance College Predictor tool to predict which college you can get based on your score.

Hope it helps !

Hello,

The minimum marks required to qualify JEE Advanced are 35% for the general category, 31.5% for OBC-NCL/EWS, and 17.5% for SC/ST/PwD candidates.

(https://jeeadv.ac.in/eligibility.html?utm_source=chatgpt.com) Given your 20.1 percentile, and you belong to PwD category, you qualify for the JEE Advance 2025.

Hope you find it useful !

Hello,

With an NTA score of 54.65, as an OBC-NCL PwD candidate:

  • Percentile : Based on previous trends , this score is likely below the expected qualifying percentile for OBC-NCL candidates, which is around 78-92.

  • Rank : Exact rank cannot be determined without official data, but it would be lower due to the score being below the typical qualifying percentile.

  • JEE Advanced Eligibility : This score is below the expected cutoff for OBC-NCL candidates to qualify for JEE Advanced.

You can also use the JEE Main Rank Predictor Tool to predict you rank and JEE Main Percentile Predictor Tool to predict your percentile.

Hope you find it useful !

Hi,

JEE Main 2025 cutoff required to qualify for JEE Advanced 2025 will be released by NTA. Minimum JEE Main marks required for JEE Advanced will be in the form of NTA percentile scores and will vary for Gen, OBC-NCL, SC, ST and Gen-EWS categories

To be eligible for JEE Advanced, a candidate needs to score above the 90th percentile in JEE Mains.

Expected JEE MAINS 2025 cutoff with category is given below:

Unreserved (UR) - 100.0000000 to 92.3362181

Gen-EWS - 93.1312650 to 79.6467818

OBC-NCL - 92.2312696 to 79.6457881

SC - 92.2312696 to 62.0923182

ST - 92.2312696 to 47.6975840

UR-PwD - 92.2041331 to 0.0015700

Hope this information will help you

Hello aspirant,

Candidates must have passed the JEE mains test (Paper 1) and rank in the top 2,50,000 (across all categories) in order to be considered. You passed with ease because the SC category cutoff for JEE Advanced qualifying is approximately 62 %.

Thank you

Hello,

Yes, you should focus on the April attempt. Here’s why:

  • Higher Percentile Possible – With focused preparation, you can improve your score significantly.
  • Better NIT/IIIT Options – Many top institutes have SC category cutoffs above 83 percentile.
  • Safer Backup – A higher percentile increases your chances of getting a good branch.
  • More Confidence – You’ll be better prepared for JEE Advanced if aiming for IITs.
  • Low Risk, High Reward – Even a small improvement can open better opportunities.
  • Prepare well and aim for at least 90+ percentile in April!

Wishing you the best !

hi ,

Congratulations on scoring 121 marks in the JEE Main 2025 exam .

Based on previous trends, a score of 121 marks in JEE Main typically corresponds to a percentile around 95. The expected cutoff for the OBC-NCL category is around 83 percentile.

Therefore, with a 95 percentile, you are likely to qualify for the JEE Advanced 2025.

Admission to National Institutes of Technology (NITs) depends on various factors, including your JEE Main rank, category, home state quota, and the specific NIT and engineering branch you are interested in. As a female candidate from the OBC-NCL category with Bihar as your home state, you have certain advantages due to reservation policies and the home state quota .

For instance, at NIT Patna, the closing ranks for the OBC-NCL category under the home state quota in previous years have been as follows:

  • Computer Science and Engineering (CSE): Around 6,254
  • Electronics and Communication Engineering (ECE): Around 7,178
  • Mechanical Engineering: Around 14,533 .

Recommendation:

Given your likely qualification for JEE Advanced and your competitive standing for NIT admissions, it would be prudent to continue your preparation for JEE Advanced 2025. This will keep your options open for admission into the prestigious Indian Institutes of Technology (IITs) and enhance your understanding of advanced concepts, which can be beneficial regardless of where you eventually enroll.

Additionally, keep an eye on the official announcements and counseling processes to make informed decisions about your applications to NITs and other institutions.

hope this helps.

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