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Trigonometric Functions of Acute Angles is considered one of the most asked concept.
31 Questions around this concept.
The expression can be written as:
If $\sin \theta=x$, find $\tan \theta$ ? (Given $\theta$ is an acute angle)
$\text{If}\; \cos \theta =\frac{1}{2},\text{ find} \: C\! osec\, \theta$
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Find $\cot \theta$ for the following figure :
$A D=\frac{2}{3} A C ; A C=4 ; A B=6$
Find $\sin x$ for this figure :
Find the value of $\mathrm{sec}^{-1}(-2)$
$\sin 30^{\circ}-\tan 45^{\circ}+\sec 60^{\circ}=$
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Trigonometric Functions of Acute Angles
We can define the trigonometric functions in terms of an angle t and the lengths of the sides of the triangle. The adjacent side (=x) is the side closest to the angle (Adjacent means “next to.”). The opposite side (=y) is the side across from the angle. The hypotenuse (=1) is the side of the triangle opposite the right angle.
Sine $\sin \mathrm{t}=\frac{\text { opposite }}{\text { hypotenuse }}$
Cosine $\quad \cos \mathrm{t}=\frac{\text { adjacent }}{\text { hypotenuse }}$
Tangent $\tan t=\frac{\text { opposite }}{\text { adjacent }}$
Reciprocal Functions: In addition to sine, cosine, and tangent, there are three more functions. These too are defined in terms of the sides of the triangle.
$\begin{aligned} & \text { Cosecant } \quad \csc t=\frac{\text { hypotenuse }}{\text { opposite }}=\frac{1}{\sin t} \\ & \text { Secent } \quad \sec t=\frac{\text { hypotenuse }}{\text { adjacent }}=\frac{1}{\cos t} \\ & \text { Cotangent } \quad \cot t=\frac{\text { adjacent }}{\text { opposite }}=\frac{1}{\tan t}\end{aligned}$
Since, the hypotenuse is the greatest side in a right-angle triangle, and can never be greater than unity and $\text{cosect}$ and $\text{sect}$ can never be less than unity.
Trigonometric Ratios of some Special Angles
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