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    How to Calculate JEE Main 2026 Marks from Answer Key: Step-by-Step Guide

    Trigonometric Ratios - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Trigonometric Functions of Acute Angles is considered one of the most asked concept.

    • 34 Questions around this concept.

    Solve by difficulty

    The expression \frac{\tan A}{1-\cot A}+\frac{\cot A}{1-\tan A}   can be written as:

    $\text{If}\; \cos \theta =\frac{1}{2},\text{ find} \: C\! osec\, \theta$

    Find $\cot \theta$ for the following figure :

    $A D=\frac{2}{3} A C ; A C=4 ; A B=6$

    Find $\sin x$ for this figure :

    A beach rescue helicopter at an altitude of 250 m from the surface of the sea finds two persons sinking in the sea. If the angle of depression for the persons in the opposite directions are $60^{\circ}$ and $30^{\circ}$, find the distance between the two persons.

    If $0\leq x<\pi/2$, then the number of values of x for which  sin x - sin 2x + sin 3x = 0, is:

    Concepts Covered - 2

    Trigonometric Functions of Acute Angles

    Trigonometric Functions of Acute Angles

    We can define the trigonometric functions in terms of an angle t and the lengths of the sides of the triangle. The adjacent side (=x) is the side closest to the angle (Adjacent means “next to.”). The opposite side (=y) is the side across from the angle. The hypotenuse (=1) is the side of the triangle opposite the right angle.

           

    Sine $\sin \mathrm{t}=\frac{\text { opposite }}{\text { hypotenuse }}$
    Cosine $\quad \cos \mathrm{t}=\frac{\text { adjacent }}{\text { hypotenuse }}$
    Tangent $\tan t=\frac{\text { opposite }}{\text { adjacent }}$

    Reciprocal Functions: In addition to sine, cosine, and tangent, there are three more functions. These too are defined in terms of the sides of the triangle.

    $\begin{aligned} & \text { Cosecant } \quad \csc t=\frac{\text { hypotenuse }}{\text { opposite }}=\frac{1}{\sin t} \\ & \text { Secent } \quad \sec t=\frac{\text { hypotenuse }}{\text { adjacent }}=\frac{1}{\cos t} \\ & \text { Cotangent } \quad \cot t=\frac{\text { adjacent }}{\text { opposite }}=\frac{1}{\tan t}\end{aligned}$

    Since, the hypotenuse is the greatest side in a right-angle triangle, \text{sint} and \text{cost } can never be greater than unity and $\text{cosect}$ and $\text{sect}$ can never be less than unity. 

    Trigonometric Ratios of some Special Angles

     

    $\text { Trigonometric Ratios of some Special Angles }$

    $\text { Angle }$ $0$ $\frac{\pi}{6}$, or $30^{\circ}$ $\frac{\pi}{4}$, or $45^{\circ}$ $\frac{\pi}{3}$, or $60^{\circ}$ $\frac{\pi}{2}$, or $90^{\circ}$
    $\text { Cosine }$ $1$ $\frac{\sqrt{3}}{2}$ $\frac{\sqrt{2}}{2}$ $\frac{1}{2}$ $0$
    $\text { Sine }$ $0$ $\frac{1}{2}$ $\frac{\sqrt{2}}{2}$ $\frac{\sqrt{3}}{2}$ $1$
    $\text { Tangent }$ $0$ $\frac{\sqrt{3}}{3}$ $1$ $\sqrt{3}$ $\text { Undefined }$
    $\text { Secant }$ $1$ $\frac{2 \sqrt{3}}{3}$ $\sqrt{2}$ $2$ $\text { Undefined }$
    $\text { Cosecant }$ $\text { Undefined }$ $2$ $\sqrt{2}$ $\frac{2 \sqrt{3}}{3}$ $1$
    $\text { Cotangent }$ $\text { Undefined }$ $\sqrt{3}$ $1$ $\frac{\sqrt{3}}{3}$ $0$

     

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    Trigonometric Functions of Acute Angles
    Trigonometric Ratios of some Special Angles

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    Reference Books

    Trigonometric Functions of Acute Angles

    Mathematics for Joint Entrance Examination JEE (Advanced) : Trigonometry

    Page No. : 2.1

    Line : 1

    Trigonometric Ratios of some Special Angles

    Mathematics for Joint Entrance Examination JEE (Advanced) : Algebra

    Page No. : 2.12

    Line : 12

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