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11 Questions around this concept.
Evaluate the value of ?
The value of is?
Allied Angles (Part 1)
Two angles are called allied if their sum or difference is a multiple of π/2
sin (900 - θ) = cos (θ)
cos (900 - θ) = sin (θ)
tan (900 - θ) = cot (θ)
csc (900 - θ) = sec (θ)
sec (900 - θ) = csc (θ)
cot (900 - θ) = tan (θ)
sin (900 + θ) = cos (θ)
cos (900 + θ) = - sin (θ)
tan (900 + θ) = - cot (θ)
csc (900 + θ) = sec (θ)
sec (900 + θ) = - csc (θ)
cot (900 + θ) = - tan (θ)
Allied Angles (Part 2)
sin (1800 - θ) = sin (θ)
cos (1800 - θ) = - cos (θ)
tan (1800 - θ) = - tan (θ)
csc (1800 - θ) = csc (θ)
sec (1800 - θ) = - sec (θ)
cot (1800 - θ) = - cot (θ)
sin (1800 + θ) = - sin (θ)
cos (1800 + θ) = - cos (θ)
tan (1800 + θ) = tan (θ)
csc (1800 + θ) = - csc (θ)
sec (1800 + θ) = - sec (θ)
cot (1800 + θ) = cot (θ)
AID TO REMEMBER
All the trigonometric function of a real number of the form 2n(π/2) ± x ( n ∈ I) (i.e. an even multiple of π/2 ± x) is numerically equal to the same function of x, with sign depending on the quadrant in which terminal side of the angles lies.
For example: cos (π + x) = cos (2(π/2) + x) = - cos (x), -ve sign chosen because (π + x) lies in 3rd quadrant and ‘cos’ is -ve in third quadrant.
All the trigonometric function of a real number of the form (2n + 1)π/2 ± x ( n ∈ I) (i.e. an even multiple of π/2 ± x) is numerically equal to the co-function of x, with sign depending on the quadrant in which terminal side of the angles lies.
Note that ‘sin’ and ‘cos’ are co-functions of each other, ‘tan’ and ‘cot’ are co-function of each other and ‘sec’ and ‘cosec’ are co-function of each other.
For example: sec (π/2 +x ) = - cosec (x), as (π/2 +x) lies in the 2nd quadrant and ‘sec’ is -ve in 2nd quadrant.
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