JEE Main B.Arch Qualifying Marks 2025 - Check Previous Year Cutoffs

Graphs of General Trigonometric Functions - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • 33 Questions around this concept.

Solve by difficulty

Range of  $f(x)=\sin|3x^3| \ \ x\epsilon R$

The number of solutions of the equation $x+2 \tan x=\frac{\pi}{2}$ in the interval $[0,2 \pi]$ is :

Which of the following can be a graph of f(x ) = $\tan 3 x ?$

JEE Main 2025: Rank Predictor | College Predictor | Marks vs Rank vs Percentile

JEE Main 2025: Sample Papers | Syllabus | Mock Tests | PYQsHigh Scoring Topics

Apply to TOP B.Tech/BE Entrance exams: VITEEE | MET | AEEE | BITSAT

$\cos x<\frac{1}{2}$ for $x$ in the interval $(0,2 \pi):$

$\cos ^{-1}\left(\frac{\sqrt{3}}{2}\right)=$

$\sin x>\frac{1}{2}$ for $x$ in the interval $(-2 \pi, 2 \pi)$ :

If $4\sin ^{2}\alpha =1,$ then the values of alpha are

Amity University Noida B.Tech Admissions 2025

Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities

Amrita Vishwa Vidyapeetham | B.Tech Admissions 2025

Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships

If $x=2\sin^{2}\alpha - \cos2\alpha, then \:\: x \:\: lies \:\: in\:\: the \:\: interval$

What is the solution of $cotx$ $>1$ in the interval $(0,2 \pi)$

JEE Main 2025 College Predictor
Know your college admission chances in NITs, IIITs and CFTIs, many States/ Institutes based on your JEE Main result by using JEE Main 2025 College Predictor.
Try Now

What is the solution set of the equation $\csc x>1$ in the interval $[0,2 \pi$ ]?

Concepts Covered - 2

Graph of Trigonometric Function (Part 1)

Graph of Trigonometric Function (Part 1)

Sine Function 

$y=f(x)=\sin (x)$

Domain is R

Range is  [-1, 1]

Cosine Function

$y=f(x)=\cos (x)$

Domain is R 

Range is [-1, 1]

Tangent Function

$y=f(x)=\tan (x)$

$\mathrm{Domain\;is\;\;\mathbb{R}-\left \{ \frac{(2n+1)\pi}{2},\;n\in\;\mathbb{I} \right \}}$

Range is R

Graph of Trigonometric Function (Part 2)

Graph of Trigonometric Function (Part 2)

Cosecant Function

$y=f(x)=\operatorname{cosec}(x)$

 

Domain is R - $\{\mathrm{n} \pi, \mathrm{n} \in \mathrm{I}$ (Integers) $\}$
Range is $\mathrm{R}-(-1,1)$
Period is $2 \pi$

Secant Function

$y=f(x)=\sec (x)$

$\mathrm{Domain\;is\;\;\mathbb{R}-\left \{ \frac{(2n+1)\pi}{2},\;n\in\;\mathbb{I} \right \}}$

The range is $\mathrm{R}-(-1,1)$
Period is $2 \pi$

Cotangent Function

$y=f(x)=\cot (x)$

 

Domain is R - $\{\mathrm{n} \pi, \mathrm{n} \in \mathrm{I}$ (Integers) $\}$
Range is $R$
Period is $2 \pi$

Study it with Videos

Graph of Trigonometric Function (Part 1)
Graph of Trigonometric Function (Part 2)

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Books

Reference Books

Graph of Trigonometric Function (Part 1)

Mathematics for Joint Entrance Examination JEE (Advanced) : Trigonometry

Page No. : 2.13

Line : 45

Graph of Trigonometric Function (Part 2)

Mathematics for Joint Entrance Examination JEE (Advanced) : Trigonometry

Page No. : 2.14

Line : 4

E-books & Sample Papers

Get Answer to all your questions

Back to top