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21 Questions around this concept.
Which of the following can be a graph of f(x ) = $\tan 3 x ?$
$\cos x<\frac{1}{2}$ for $x$ in the interval $(0,2 \pi):$
$\cos ^{-1}\left(\frac{\sqrt{3}}{2}\right)=$
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$\sin x>\frac{1}{2}$ for $x$ in the interval $(-2 \pi, 2 \pi)$ :
If $4\sin ^{2}\alpha =1,$ then the values of alpha are
If $x=2\sin^{2}\alpha - \cos2\alpha, then \:\: x \:\: lies \:\: in\:\: the \:\: interval$
For what x (x is in 2nd quadrant) such that $0< cosec\, x\; < 2$?
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Which is the graph of $\cot x$?
Which is the graph of $\sec x$ ?
Graph of Trigonometric Function (Part 1)
Sine Function
$y=f(x)=\sin (x)$
Domain is R
Range is [-1, 1]
Cosine Function
$y=f(x)=\cos (x)$
Domain is R
Range is [-1, 1]
Tangent Function
$y=f(x)=\tan (x)$
$\mathrm{Domain\;is\;\;\mathbb{R}-\left \{ \frac{(2n+1)\pi}{2},\;n\in\;\mathbb{I} \right \}}$
Range is R
Graph of Trigonometric Function (Part 2)
Cosecant Function
$y=f(x)=\operatorname{cosec}(x)$
Domain is R - $\{\mathrm{n} \pi, \mathrm{n} \in \mathrm{I}$ (Integers) $\}$
Range is $\mathrm{R}-(-1,1)$
Period is $2 \pi$
Secant Function
$y=f(x)=\sec (x)$
$\mathrm{Domain\;is\;\;\mathbb{R}-\left \{ \frac{(2n+1)\pi}{2},\;n\in\;\mathbb{I} \right \}}$
The range is $\mathrm{R}-(-1,1)$
Period is $2 \pi$
Cotangent Function
$y=f(x)=\cot (x)$
Domain is R - $\{\mathrm{n} \pi, \mathrm{n} \in \mathrm{I}$ (Integers) $\}$
Range is $R$
Period is $2 \pi$
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