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Sticking Of Person With The Wall Of Rotor - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
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5 Questions around this concept.
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As shown in the figure, a person of mass ' $m$ ' remains stuck to the wall of rotating rotor. What should be the minimum value of angular velocity $\omega$ [coefficient of friction between wall and man is $\mu_{\text {] }}$
A man is rest against the inner wall of a rotor which is moving with angular velocity . If the radius of the rotor is 2m and the coefficient of static friction between wall and the person is 0.2 . Find minimum angular velocity (in rad/sec) for man to be at rest. (g= 10m/s2)
A person stands in contact against the inner wall of a rotor of radius r. The coefficient of friction between the wall and the clothing is μ and the rotor is rotating about a vertical axis. What is the minimum angular speed of the rotor so that the person does not slip downward?
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A man of 50 pounds was made to stand against the inner wall of a hollow cylinder and the rotor of radius 5m is rotating at its vertical axis, and the coefficient of friction between the wall and his clothing is 0.35. What is the minimum angular speed of the rotor so that the person does not slip downward?
Concepts Covered - 1
Sticking of Person with the wall of Rotor(Death well)
$\begin{aligned} & \mathrm{F}=\text { weight of person (mg) } \\ & \mu R=m g \\ & \mu F_c=m g \\ & \mu m \omega_{\min }^2 r=m g \\ & \therefore \omega_{\min }=\sqrt{\frac{g}{\mu r}} \\ & \text { Where } \mathrm{F}=\text { friction force } \\ & \mathrm{F}_{\mathrm{c}}=\text { centrifugal force } \\ & \omega_{\min }=\text { minimum angular velocity } \\ & \mu={ }_{\text {coefficient of friction }} \\ & \mathrm{r}=\text { radius of Rotor }\end{aligned}$
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