VIT - VITEEE 2025
National level exam conducted by VIT University, Vellore | Ranked #11 by NIRF for Engg. | NAAC A++ Accredited | Last Date to Apply: 31st March | NO Further Extensions!
Series Involving Binomial Coefficients is considered one of the most asked concept.
140 Questions around this concept.
The sum of the series $\binom{10}{0}-\binom{10}{1}+\binom{10}{2}-\binom{10}{3}+\binom{10}{4}+\ldots+\binom{10}{10}$ is
In the expansion of the sum of the coefficient of the terms is
In the expansion of the sum of coefficients of odd powers of x is
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If so, then the value of
In the expansion of , the sum of the coefficient of odd powers of x is
In the expansion of , the sum of the coefficient of the terms is.
${ }^5 C_2+{ }^6 C_3+{ }^7 C_4+----+{ }^{11} C_8$ equals
National level exam conducted by VIT University, Vellore | Ranked #11 by NIRF for Engg. | NAAC A++ Accredited | Last Date to Apply: 31st March | NO Further Extensions!
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The number of non-zero terms is the expansion of $\left [ (1+3\sqrt{2}\: x)^{9} +(1-3\sqrt{2}\: x)^{9}\right ]$ is
What is the symbol for if and only if
1. Sum of Binomial Coefficients
$
\begin{aligned}
& C_0+\mathrm{C}_1+C_2+C_3+\ldots \ldots+C_n=2^n \\
& \text { or } \sum_{r=0}^n{ }^n C_r=2^n
\end{aligned}
$
2. Sum of Binomial coefficients with alternate sign
$
\begin{aligned}
& C_0-\mathrm{C}_1+C_2-C_3+\ldots \ldots+(-1)^n C_n=0 \\
& \text { or } \sum_{r=0}^n(-1)^r{ }^n C_r=0
\end{aligned}
$
3. Sum of the Binomial coefficients of the odd terms \& Sum of the Binomial coefficients of the even terms
Adding the above two series we get,
$
\begin{aligned}
& 2 \cdot\left(\mathrm{C}_0+\mathrm{C}_2+\mathrm{C}_4+\ldots \ldots\right)=2^n \\
& \mathrm{C}_0+\mathrm{C}_2+\mathrm{C}_4+\ldots \ldots=2^{n-1}
\end{aligned}
$
Similarly, on subtracting we get,
$
\mathrm{C}_1+\mathrm{C}_3+\mathrm{C}_5 \ldots \ldots=2^{n-1}
$
Hence, the sum of the binomial coefficients of the odd terms = Sum of the binomial coefficients of the even terms
$
\text { I.e. } C_1+C_3+C_5 \ldots \ldots=C_0+C_2+C_4+\ldots \ldots=2^{n-1}
$
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