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    JEE Main 2026 Exam Analysis For Session 2 – Shift Wise Difficulty Level, Paper Review

    Series Involving Binomial Coefficients - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

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    • Series Involving Binomial Coefficients is considered one of the most asked concept.

    • 143 Questions around this concept.

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    The sum of the series $\binom{10}{0}-\binom{10}{1}+\binom{10}{2}-\binom{10}{3}+\binom{10}{4}+\ldots+\binom{10}{10}$ is

     

    In the expansion of (1+x)^5 the sum of the coefficient of the terms is

    In the expansion of (1+x)^n  the sum of coefficients of odd powers of x is

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    If \\(1+x)^n=C_0+C_1 x+C_2 x^2+\ldots+C_n x^nso, then the value of C_0+C_2+C_4+C_6+\ldots

    In the expansion of (1+x)^{50}, the sum of the coefficient of odd powers of x is

    In the expansion of (1+x)^5, the sum of the coefficient of the terms is.

    ${ }^5 C_2+{ }^6 C_3+{ }^7 C_4+----+{ }^{11} C_8$ equals

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    The number of non-zero terms is the expansion of $\left [ (1+3\sqrt{2}\: x)^{9} +(1-3\sqrt{2}\: x)^{9}\right ]$ is

    What is the symbol for if and only if

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    Concepts Covered - 1

    Series Involving Binomial Coefficients

    1. Sum of Binomial Coefficients 

    $
    \begin{aligned}
    & C_0+\mathrm{C}_1+C_2+C_3+\ldots \ldots+C_n=2^n \\
    & \text { or } \sum_{r=0}^n{ }^n C_r=2^n
    \end{aligned}
    $

    2. Sum of Binomial coefficients with alternate sign

    $
    \begin{aligned}
    & C_0-\mathrm{C}_1+C_2-C_3+\ldots \ldots+(-1)^n C_n=0 \\
    & \text { or } \sum_{r=0}^n(-1)^r{ }^n C_r=0
    \end{aligned}
    $

    3. Sum of the Binomial coefficients of the odd terms \& Sum of the Binomial coefficients of the even terms

    Adding the above two series we get,

    $
    \begin{aligned}
    & 2 \cdot\left(\mathrm{C}_0+\mathrm{C}_2+\mathrm{C}_4+\ldots \ldots\right)=2^n \\
    & \mathrm{C}_0+\mathrm{C}_2+\mathrm{C}_4+\ldots \ldots=2^{n-1}
    \end{aligned}
    $
    Similarly, on subtracting we get,

    $
    \mathrm{C}_1+\mathrm{C}_3+\mathrm{C}_5 \ldots \ldots=2^{n-1}
    $
    Hence, the sum of the binomial coefficients of the odd terms = Sum of the binomial coefficients of the even terms

    $
    \text { I.e. } C_1+C_3+C_5 \ldots \ldots=C_0+C_2+C_4+\ldots \ldots=2^{n-1}
    $

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    Series Involving Binomial Coefficients

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