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Multinomial Theorem - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • 34 Questions around this concept.

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The coefficient of x^6   in the expansion of (1+x^2-x^3)^8  is

If number of terms in the expansion of (x-2 y+3 z)^n are 45, then n=
 

(1+x)\left(1+x+x^2\right)\left(1+x+x^2+x^3\right) \ldots \ldots\left(1+x+x^2+\ldots \ldots+x^{100}\right) when written in the ascending power of x then the highest exponent of x is......

The number of terms in the expansion of \small (a+b+c)^n  will be:

Concepts Covered - 1

Multinomial Theorem

As a binomial has two terms raised to some power, similarly a multinomial has multiple terms raised to some power.
$\mathrm{eg}_{,}\left(\mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\ldots \ldots .+\mathrm{x}_{\mathrm{k}}\right)^n \quad($ Where n is a positive integer)
Expansion for the multinomial $\left(\mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\ldots \ldots . .+\mathrm{x}_{\mathrm{k}}\right)^n$ is

$
\left(\mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\ldots .+\mathrm{x}_{\mathrm{k}}\right)^{\mathrm{n}}=\sum \frac{\mathrm{n}!}{\alpha_{1}!\alpha_{2}!\alpha_{3}!\ldots \alpha_{\mathrm{k}}!}\left(\mathrm{x}_1^{\alpha_1} \cdot \mathrm{x}_2^{\alpha_2} \cdot \mathrm{x}_3^{\alpha_1} \cdot \ldots \cdot \mathrm{x}_{\mathrm{k}}^{\alpha_{\mathrm{k}}}\right)
$

with $a_1+a_2+a_3+\ldots .+a_k=n$,
and $a_1, a_2, a_3, \ldots, a_k \in W \mid$
In particular,

$
(\mathrm{a}+\mathrm{b}+\mathrm{c})^{\mathrm{n}}=\sum \frac{\mathrm{n!}}{(\alpha!)(\beta!)(\gamma!)} \mathrm{a}^\alpha \mathrm{b}^\beta \mathrm{c}^\gamma
$
The number of distinct terms in the multinomial expansion $\left(\mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\ldots \ldots .+\mathrm{x}_{\mathrm{k}}\right)^{\mathrm{n}}{ }_{\text {is }}{ }^{\mathrm{n}+\mathrm{k}-1} \mathrm{C}_{\mathrm{k}-1}$

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Multinomial Theorem

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