7 Questions around this concept.
A car is going on a convex bridge with a radius R. The driver maintains a constant speed , as the car ascends on the bridge, the normal force on it:
A car moves on a concave bridge of radius R, then the maximum reaction force on the car will be:
[let the mass of the car be m]
A car of mass m is moving on a concave bridge of radius r with velocity v as shown in the diagram for what value of the reaction on the car by the bridge will be maximum.
Where $\theta$ is the angle made by a vertical line

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A car is moving on convex bridge of radius r with velocity v for what maximum value of v, car will loose contact with bridge
When bridge is concave

$\begin{aligned} & \text { Centripetal force }=R-m g \cos \theta=\frac{m v^2}{r} \\ & \text { Reaction } \mathrm{R}=m g \cos \theta+\frac{m v^2}{r} \\ & \mathrm{R}=\text { reaction } \\ & \mathrm{V}=\text { velocity } \\ & \mathrm{r}=\text { radius }\end{aligned}$
When the bridge is convex

$\begin{aligned} & F_c=m g \cos \theta-R=\frac{m v^2}{r} \\ & R=m g \cos \theta-\frac{m v^2}{r} \\ & \mathrm{R}=\text { reaction } \\ & \mathrm{F}_{\mathrm{c}}=\text { centripetal force } \\ & \mathrm{mg}=\text { weight } \\ & \theta=\text { angle of } \mathrm{R} \text { with vertical } \\ & \mathrm{V}=\text { tangential velocity }\end{aligned}$
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