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Motion Of Connected Blocks Over Pulley - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
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Motion of connected blocks over pulley is considered one the most difficult concept.
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44 Questions around this concept.
Solve by difficulty
Two masses m1 = 5kg and m2 = 4.8 kg tied to a string are hanging over a light frictionless pulley. What is the acceleration (in m/s2 ) of the masses when lifted free to move?
( g = 9.8 m/s2 )
A light string passing over a smooth light pulley connects two blocks of masses m1 and m2 ( vertically) . If the acceleration of the system is g/8, then the ratio of the masses is
Two masses of 10 kg and 9 kg are connected by a string that passes over a smooth pulley; What is the tension in the string $\left(g=9.81 \mathrm{~ms}^{-2}\right)$
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Three masses each of 4 kg are connected by a string that passes through a smooth pulley; Tension between mass b and c?
Direction : In the following question , a statement of Assertion (A) is followed by a statement of reason (R) . Mark the correct choice as:
Assertion : The tension force on a body always act away from the body.
Reason : Tension force are always pushing force.
Two blocks of masses 5kg and 10kg are connected to a pulley as shown in fig. What will be the acceleration if the pulley is set free?
What is the mechanical advantage of a single fixed pulley?
The system shown is released at rest. Speed of block A (in m/s), after B has descended by 2 cm is
As shown in the figure, a block of mass m = 200 g is suspended by a string. A force F is applied slowly at the lower end of the string.What will be the maximum value of F if bearing strength of the string is 5N?
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Try NowA monkey of mass ${ }^{\prime} m$ ' is climbing a rope hanging from the roof with acceleration ${ }^{\prime} a^{\prime}$. The coefficient of static friction between the body of the monkey and the rope is $\mu$. The value of friction force on the monkey and tension in the string are respectively.
Concepts Covered - 2
Motion of connected blocks over pulley
Equation of motion for $m_1$
$
F_{n e t}=T-m_1 g=m_1 a
$
Equation of Motion for $m_2$
$
\begin{aligned}
& F_{\text {net }}=m_2 g-T=m_2 a \\
& a=\frac{\left[m_2-m_1\right] g}{m_1+m_2} \\
& T=\frac{2 m_1 m_2 g}{m_1+m_2}
\end{aligned}
$
When one Block is hanging from a rope and one on the table
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When one Block is hanging, other is on the Table
$\begin{aligned} a & =\frac{m_2 g}{m_1+m_2} \\ T & =\frac{m_1 m_2 g}{m_1+m_2}\end{aligned}$
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Three blocks, two are hanging and one is at the rest on the smooth horizontal table
$
\begin{aligned}
& m_1 a=m_1 g-T_1 \\
& m_2 a=T_2-m_2 g \\
& T_1-T_2=M a
\end{aligned}
$
$
\begin{aligned}
& a=\frac{\left(m_1-m_2\right) g}{m_1+m_2+M} \\
& T_1=\frac{m_1\left(2 m_2+M\right) g}{\left(m_1+m_2+M\right)} \\
& T_2=\frac{m_2\left(2 m_1+M\right) g}{\left(m_1+m_2+M\right)}
\end{aligned}
$
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