Amity University-Noida B.Tech Admissions 2026
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Modulus of complex number and its Properties is considered one the most difficult concept.
68 Questions around this concept.
If $\mathrm{S}=\{\mathrm{z} \in \mathrm{C}:|\mathrm{z}-\mathrm{i}|=|\mathrm{z}+\mathrm{i}|=|\mathrm{z}-1|\}$, then, $\mathrm{n}(\mathrm{S})$ is :
$z \bar{z}=$
If z is origin, then $\left | z \right |=$
JEE Main 2026: Result OUT; Check Now | Final Answer Key Link
JEE Main 2026 Tools: College Predictor
JEE Main 2026: Session 2 Registration Link | Foreign Universities in India
If $|z|=5 {\text { then }} \operatorname{Re}(z)$ can satisfy
Which value(s) of $\left|Z_1-Z_2\right|$ is/are acceptable, if $\left|Z_1\right|=7$ and $\left|Z_2\right|=41$
The magnitude and amplitude of $\frac{(1+i \sqrt 3 )(2+2i)}{(\sqrt 3 - i)}$ are respectively:
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Last Date to Apply: 28th Feb | Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
If $\left | z_{1}z_{2} \right |=5\sqrt{10},$
$| z_{1} |=5\sqrt{2}$
then $\left | z_{2}\right |=?$
Modulus and amplitude of the complex number $\small \frac{1-2i}{1-(1+i)^2}$ is
If z = x + iy is a complex number. Then, the modulus of z, denoted by | z |, is the distance of z from the origin in the Argand plane, and it is a non-negative real number equal to $\sqrt{\mathrm{x}^2+\mathrm{y}^2}$.
i.e. |z| =$\sqrt{x^2+y^2}$.
Every complex number can be represented as a point in the argand plane with the x-axis as the real axis and the y-axis as the imaginary axis.
$|z|=\sqrt{x^2+y^2}=r$ (length r from origin to point (x,y))
Properties of Modulus
i) $|z| \geq 0$
ii) $|z|=0$, iff $z=0$ and $|z|>0$, iff $z \neq 0$
iii) $-|z| \leq \operatorname{Re}(z) \leq|z|$ and $-|z| \leq \operatorname{Im}(z) \leq|z|$
iv) $|z|=|\bar{z}|=|-z|=|-\bar{z}|$
v) $z \bar{z}=|z|^2$
vi) $\left|z_1 z_2\right|=\left|z_1\right|\left|z_2\right| . \quad$ Thus, $\left|z^n\right|=|z|^n$
vii) $\left|\frac{z_1}{z_2}\right|=\frac{\left|z_1\right|}{\left|z_2\right|}$
viii) $\left|z_1 \pm z_2\right| \leq\left|z_1\right|+\left|z_2\right|_{\text {(Triangle inequality) this can be generalised for } \mathrm{n} \text { complex numbers. }}$
ix) $\left|z_1 \pm z_2\right| \geq\left|\left|z_1\right|-\left|z_2\right|\right|$
"Stay in the loop. Receive exam news, study resources, and expert advice!"
