13 Questions around this concept.
Correct result for $\left ( 4+4\sqrt{3}\:\: i \right )^{\frac{4}{5}}$ is :
What is the polar term of $z=-4+4 i$ ?
In polar form, we represent the complex number through the argument and modulus value of complex numbers.
Let $z=x+i y$ be a complex number,
And we know that
$|z|=\sqrt{x^2+y^2}=r$
And let arg(z) = θ

From the figure, $x=|z| \cos (\theta)=r \cos (\theta)$
and $y=|z| \sin (\theta)=r \sin (\theta)$
So, $z=x+i y=r \cos (\theta)+i . r \sin (\theta)=r(\cos (\theta)+i . \sin (\theta))$
This form is called polar form with $r=$ principal value of $\arg (z)$ and $r=|z| . \mid$
For general values of the argument
$\mathrm{z}=\mathrm{r}[\cos (2 \mathrm{n} \pi+\theta)+i \sin (2 \mathrm{n} \pi+\theta)]$, where $n \in$ Integer
"Stay in the loop. Receive exam news, study resources, and expert advice!"
This round of applications closing on 15th July | Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
100+ Recruiters | 1200+ Placements of 2026 Batch | NBA & NAAC Accredited | Highest CTC 37 LPA
NAAC A++ Grade | Highest Package-30 LPA | 400+ Recruiters
NAAC A+ Grade | Ranked 503 Globally (QS World University Rankings 2026)
40 LPA Highest Package | Up to 100% Scholarship worth 24 Crore via GUTS exam
Last Date to Apply: 15th July | Ranked #43 among Engineering colleges in India by NIRF | Get Upto 100% Scholarships | Spot Admissions via CUET
Explore on Careers360
Student Community: Where Questions Find Answers