MEDIUMUPES B.Tech Admissions 2025
ApplyRanked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 28th April
Maximum Length Of Hung Chain - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
-
6 Questions around this concept.
Solve by difficulty
A heavy uniform chain lies on a horizontal table top. If the coefficient of friction between the chain and the table surface is 0.25, then the maximum fraction of the length of the chain that can hang over one edge of the table is
Length of chain is $L$ and coefficient of static friction is $\mu$. Calculate the maximum length of the chain which can be hung from the table without sliding. Maximum length of hung chain
A uniform rope of length I lies on a table. If the coefficient of friction is $\mu$ then the maximum length $x$ of the part of this rope which can overhang from the edge of the table without sliding down is
JEE Main 2025: Session 2 Result Out; Direct Link
JEE Main 2025: College Predictor | Marks vs Percentile vs Rank
New: JEE Seat Matrix- IITs, NITs, IIITs and GFTI | NITs Cutoff
Latest: Meet B.Tech expert in your city to shortlist colleges
The length of the chain is 1 m and the coefficient of static friction is $\mu$. Calculate the maximum length of chain which can be hung from the table without sliding $(\mu=0.5)$
A uniform rope of total length $l$ is at rest on a table with fraction $f$ of its length hanging (see figure). If the coefficient of friction between the table and the chain is $\mu$ then
Concepts Covered - 1
Maximum Length of Hung Chain
A uniform chain of length l is placed on the table in such a manner that its l' part is hanging over the edge of the table without sliding.
$
\mu=\frac{m_2}{m_1}=\frac{\text { mass hanging from table }}{\text { mass on table }}
$
The chain will have uniform linear density.
So the ratio of mass and ratio of length for any part of the chain will be equal.
$
\begin{aligned}
& \mu=\frac{\text { length of part hanging from table }}{\text { length of part on table }}=\frac{l^{\prime}}{l-l^{\prime}} \\
& l^{\prime}=\frac{\mu l}{(\mu+1)}
\end{aligned}
$
Where $l=$ length of chain
$l^{\prime}=$ chain hanging
$
\left(l-l^{\prime}\right)=\text { chain lying on table }
$
Study it with Videos
Maximum Length of Hung Chain"Stay in the loop. Receive exam news, study resources, and expert advice!"
Get Answer to all your questions
JEE Main Articles
Apr 22, 2025
Back to top