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    How to Get Admission in NITs via JEE Main 2026? – Complete Guide

    Maximum Length Of Hung Chain - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • 5 Questions around this concept.

    Solve by difficulty

    Length of chain is $L$ and coefficient of static friction is $\mu$. Calculate the maximum length of the chain which can be hung from the table without sliding. Maximum length of hung chain

     

    A uniform rope of length I lies on a table. If the coefficient of friction is $\mu$ then the maximum length $x$ of the part of this rope which can overhang from the edge of the table without sliding down is

     

    The length of the chain is 1 m and the coefficient of static friction is $\mu$. Calculate the maximum length of chain which can be hung from the table without sliding $(\mu=0.5)$

    A uniform rope of total length $l$ is at rest on a table with fraction $f$ of its length hanging (see figure). If the coefficient of friction between the table and the chain is $\mu$ then


     

    Concepts Covered - 1

    Maximum Length of Hung Chain

    A uniform chain of length l is placed on the table in such a manner that its l' part is hanging over the edge of the table without sliding.

    $
    \mu=\frac{m_2}{m_1}=\frac{\text { mass hanging from table }}{\text { mass on table }}
    $


    The chain will have uniform linear density.
    So the ratio of mass and ratio of length for any part of the chain will be equal.

    $
    \begin{aligned}
    & \mu=\frac{\text { length of part hanging from table }}{\text { length of part on table }}=\frac{l^{\prime}}{l-l^{\prime}} \\
    & l^{\prime}=\frac{\mu l}{(\mu+1)}
    \end{aligned}
    $


    Where $l=$ length of chain
    $l^{\prime}=$ chain hanging

    $
    \left(l-l^{\prime}\right)=\text { chain lying on table }
    $
     

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    Maximum Length of Hung Chain

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