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    How to Score High in JEE Main 2026 Physics – Tips, Tricks & Important Topics

    Banking Of Road - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Banking of Road is considered one the most difficult concept.

    • 12 Questions around this concept.

    Solve by difficulty

    A train is moving with a speed of $12 \mathrm{~m} / \mathrm{s}$ on rails which are $1.5 \mathrm{~m}$ apart. To negotiate a curve of radius $400 \mathrm{~m}$, the height by which the outer rail should be raised with respect to the inner rail is (Given, $g=10 \mathrm{~m} / \mathrm{s}^2$ )

    A car of $800 \mathrm{~kg}$ is taking turn on a banked road of radius $300 \mathrm{~m}$ and angle of banking $30^{\circ}$. If the coefficient of static friction is 0.2 then the maximum speed with which the car can negotiate the turn safely: $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2, \sqrt{3}=1.73\right)$

    A car of mass m is moving on a concave bridge of radius r with velocity v as shown in the diagram for what value of the reaction on the car by the bridge will be maximum. 

    Where $\theta$ is the angle made by a vertical line 

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    Concepts Covered - 1

    Banking of Road
    1. Without friction

     

    From figure

    $
    \begin{aligned}
    & R \cos \theta=m g \\
    & R \sin \theta=\frac{m v^2}{r} \\
    & \tan \theta=\frac{v^2}{r g} \\
    & \tan \theta=\frac{\omega^2 r}{g}=\frac{V \omega}{g}=\frac{h}{l} \\
    & \mathrm{~h}=\text { height of outer edge from the ground level } \\
    & l=\text { width of the road } \\
    & \mathrm{r}=\text { radius }
    \end{aligned}
    $
     

    1.  If friction is also present

    $
    \frac{V^2}{r g}=\frac{\mu+\tan \theta}{1-\mu \tan \theta}
    $


    Where $\theta=$ angle of banking
    $\mu=$ coefficient of friction
    $V=$ velocity
    Maximum speed on a banked frictional road

    $
    V=\sqrt{\frac{r g(\mu+\tan \theta)}{1-\mu \tan \theta}}
    $
     

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    Banking of Road

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