Hii

If you are not able to prepare this year, then go for drop then. Taking drop will help you qith peraration for jee mains and also jee advanced.

Coming to second part of question, if you have appeared for class 12 this year, the  you are eligible to aply

Hello Sayam!

For getting CSE in IIT GUWAHTI and IIT HYDERABAD it depends on different round .For I round opening rank is around 415 and closing rank is 617 in guwahati.In IIT Hyderabad opening rank is opening rank is around 522 and closing rank is around 967. This rank is

Firstly NTA will published jee main paper 1 percentile score. Previous year cut off for qualifying jee main are 74 %marks for general, obc 49 %marks and SC 25 % marks and ST 24%marksyou Crosses these percentile marks you have chance to sit in another level i. e jee advance.

second shift on 12th jan 2019 and got 83.7

As per the previous norms generally any candidate use to get rank upto 2.5 lac, it means that if someone is under 2.5 lac rank is eligible for JEE Advanced. So one can do simple calculation to compute that if someone is scoring more than 78 or 80 percentile will

Hey Girjesh.

See the last rank required to get selected to apply for the JEE ADVANCED is about 240000. The students who have their rank under this are eligible to give the JEE ADVANCED paper. One more criteria that is required for the application of the exam is that u

e) Phenols

Acidity, electrophilic substitution reactions (halogenation, nitration and sulphonation); Reimer-Tieman reaction, Kolbe reaction.

f) Characteristic reactions of the following (including those mentioned above)

Alkyl halides: rearrangement reactions of alkyl carbocation, Grignard reactions, nucleophilic substitution reactions; Alcohols: esterification, dehydration and oxidation, reaction with sodium, phosphorus halides, ZnCl2/concentrated HCl, conversion of