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Stokes' Law And Terminal Velocity - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Stokes' law & Terminal Velocity is considered one the most difficult concept.

  • 37 Questions around this concept.

Solve by difficulty

Spherical balls of radius R are falling in a viscous fluid of viscosity \eta with a velocity\nu. The retarding viscous force acting on the spherical ball is:

A spherical solid ball of volume V is made of a material of density \rho1. It is falling through a liquid of density \rho2 (\rho2  < \rho1). Assume that the liquid applies a viscous force on the ball that is proportional to the square of its speed \nu ,i.e.,F_{viscous}= -kv^{2}\left ( k> 0 \right ). The terminal speed of the ball is

The velocity of a small ball of mass ' $\mathrm{m}^{\prime}$ and density $\mathrm{d}_1$, when dropped in a container filled with glycerine, becomes constant after some time. If the density of glycerine is $\mathrm{d}_2$, then the viscous force acting on the ball will be:

From amongst following curves, which one show the variation of the velocity v with time t for a small-sized spherical body (release from rest) falling vertically downwards in a long column of a viscous liquid is best represented by

 

If the terminal speed of a sphere of gold \left ( density = 19.5 kg/m^{3} \right ) is 0.2 m/s in a viscous liquid \left ( density = 1.5 kg/m^{3} \right ), find the terminal speed (in m/sec) of a sphere of silver \left ( density = 10.5 kg/m^{3} \right ) of the same size in the same liquid.

A spherical ball with radius R is descending at a velocity of v through a viscous fluid with viscosity η. Which of the following statements is correct regarding the viscous force?

Which of the diagrams in Figure correctly shows the change in kinetic energy of an iron sphere falling freely in a lake having sufficient depth to impart it a terminal velocity?

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Which of the following is true about positive terminal velocity - 

(i) The body attains constant velocity in a downward direction

(ii) Example - Air bubble in a liquid 

 

Which of the following is true about the terminal velocity of a spherical body in a viscous fluid - 

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A small sphere of mass m is dropped from a great height. After it has fallen 100 m, it has attained its terminal velocity and continues to fall at that speed. The work done by air friction against the sphere during the first 100 m of fall is:

Concepts Covered - 1

Stokes' law & Terminal Velocity
  • Stokes' law-

When a body moves through a fluid then The fluid exerts a viscous force on the body to oppose its motion.

And according to Stokes' law, the magnitude of the viscous force depends on the shape and size of the body, its speed and the viscosity of the fluid.

So for the below figure

If a sphere of radius r moves with velocity v through a fluid of viscosity \eta

Then using  Stokes' law the viscous force (F) opposing the motion of the sphere is given by

$
F=6 \pi \eta r v
$


Where
$\eta$ - coefficient viscosity
$r$ - radius
$v-v e l o c i t y$

  • Terminal Velocity-

When the spherical body is dropped in a viscous fluid, it is first accelerated and then it's acceleration becomes zero and it attains a constant velocity and this constant velocity is known as terminal velocity.

For a  spherical body of radius r is dropped in a viscous fluid, The forces acting on it are shown in the below figure.

 

So Forces acting on the body are

1. Weight of Body (W)

$
W=m g=\frac{4}{3} \pi r^3 \rho g
$


Where $\rho \rightarrow$ density of body
2. Buoyant/ Thrust Force (T of $F_B$ )

$
T=F_B=\frac{4}{3} \pi r^3 \sigma g
$

where $\sigma \rightarrow$ density of fluid
3. Viscous force (F)

$
F=6 \pi \eta r v
$


So when the body attains terminal velocity the net force acting on the body is zero.
Apply force balance

$
\begin{aligned}
& F_B+F=W \\
& \rightarrow 6 \pi \eta r v+\frac{4}{3} \pi r^3 \sigma g=\frac{4}{3} \pi r^3 \rho g \\
& \rightarrow 6 \pi \eta r v=\frac{4}{3} \pi r^3 g(\rho-\sigma) \\
& \rightarrow v_t=\frac{2}{9} \frac{r^2(\rho-\sigma)}{\eta} g
\end{aligned}
$


Where $v_T=$ terminal velocity

                From this formula, we can say that

  • Terminal velocity depends on the radius of the sphere/body.
  • Greater the density of solid greater will be the terminal velocity     
  • Greater the density and viscosity of the fluid lesser will be the terminal velocity.      
  • If ρ > σ then Terminal velocity will be positive.

            I.e Spherical body attains constant velocity in a downward direction.     

  •  If ρ < σ then Terminal velocity will be negative.

         I.e Spherical body attains constant velocity in an upward direction.

  •  Terminal velocity graph

                  

 

 

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Stokes' law & Terminal Velocity

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Stokes' law & Terminal Velocity

Physics Part II Textbook for Class XI

Page No. : 264

Line : 5

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