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    How to Build an Effective Study Plan for JEE 2027: Expert Strategies for Consistent Performance

    Sticking Of A Block With Accelerated Cart - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • 2 Questions around this concept.

    Solve by difficulty

    As shown here, in the figure, a cart C with mass M moving with acceleration 'b'. If the coefficient of friction between the block A having mass m and the cart is μ, then, acceleration of cart and block system is independent of:

    As shown here, in the figure, cart C is moving with acceleration ' b '. If the coefficient of friction between block A and the cart is $\mu$ then what is the maximum value of 'b' so that the block $A$ does not fall?

     

    Concepts Covered - 1

    Sticking of a Block With Accelerated Cart

    While solving with the help of the concept of pseudo force.

    When a cart moves with some acceleration toward right then a pseudo force (ma) acts on block toward left.

    This force (ma) is an action force by a block on the cart. 

     

    Now block will remain static w.r.t.cart. If friction force= μR≥mg

    For equilibrium condition

    $
    \begin{aligned}
    & \mu m a \geq m g \\
    & a \geq \frac{g}{\mu}
    \end{aligned}
    $


    $
    \begin{aligned}
    & \mathrm{R}=\mathrm{ma} \\
    & \therefore \quad a_{\min }=\frac{g}{\mu}
    \end{aligned}
    $


    SO minimum force applied on the cart so that block will remain static w.r.t.cart.

    $
    F_{\min }=(M+m) \frac{g}{\mu}
    $

    where
    $F_{\text {min }}=$ Minimum force
    $a_{\text {min }}=$ minimum acceleration cart
    $\mathrm{M}, \mathrm{m}$ are masses of the cart and block respectively

     

     

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    Sticking of a Block With Accelerated Cart

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