HBTU Kanpur JEE Mains Cutoff 2025: Expected Ranks and Trends

Sticking Of A Block With Accelerated Cart - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • 2 Questions around this concept.

Solve by difficulty

As shown here, in the figure, a cart C with mass M moving with acceleration 'b'. If the coefficient of friction between the block A having mass m and the cart is μ, then, acceleration of cart and block system is independent of:

As shown here, in the figure, cart C is moving with acceleration ' b '. If the coefficient of friction between block A and the cart is $\mu$ then what is the maximum value of 'b' so that the block $A$ does not fall?

 

Concepts Covered - 1

Sticking of a Block With Accelerated Cart

While solving with the help of the concept of pseudo force.

When a cart moves with some acceleration toward right then a pseudo force (ma) acts on block toward left.

This force (ma) is an action force by a block on the cart. 

 

Now block will remain static w.r.t.cart. If friction force= μR≥mg

For equilibrium condition

$
\begin{aligned}
& \mu m a \geq m g \\
& a \geq \frac{g}{\mu}
\end{aligned}
$


$
\begin{aligned}
& \mathrm{R}=\mathrm{ma} \\
& \therefore \quad a_{\min }=\frac{g}{\mu}
\end{aligned}
$


SO minimum force applied on the cart so that block will remain static w.r.t.cart.

$
F_{\min }=(M+m) \frac{g}{\mu}
$

where
$F_{\text {min }}=$ Minimum force
$a_{\text {min }}=$ minimum acceleration cart
$\mathrm{M}, \mathrm{m}$ are masses of the cart and block respectively

 

 

Study it with Videos

Sticking of a Block With Accelerated Cart

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

Back to top