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2 Questions around this concept.
As shown here, in the figure, a cart C with mass M moving with acceleration 'b'. If the coefficient of friction between the block A having mass m and the cart is μ, then, acceleration of cart and block system is independent of:
As shown here, in the figure, cart C is moving with acceleration ' b '. If the coefficient of friction between block A and the cart is $\mu$ then what is the maximum value of 'b' so that the block $A$ does not fall?
While solving with the help of the concept of pseudo force.
When a cart moves with some acceleration toward right then a pseudo force (ma) acts on block toward left.
This force (ma) is an action force by a block on the cart.
Now block will remain static w.r.t.cart. If friction force= μR≥mg
For equilibrium condition
$
\begin{aligned}
& \mu m a \geq m g \\
& a \geq \frac{g}{\mu}
\end{aligned}
$
$
\begin{aligned}
& \mathrm{R}=\mathrm{ma} \\
& \therefore \quad a_{\min }=\frac{g}{\mu}
\end{aligned}
$
SO minimum force applied on the cart so that block will remain static w.r.t.cart.
$
F_{\min }=(M+m) \frac{g}{\mu}
$
where
$F_{\text {min }}=$ Minimum force
$a_{\text {min }}=$ minimum acceleration cart
$\mathrm{M}, \mathrm{m}$ are masses of the cart and block respectively
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