Skidding Of Vehicle On A Level Road MCQ - Practice Questions & Answers

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A modern Grand - prix racing car of mass $m$ is travelling on a flat track in a circular arc of radius R with a speed v . If the coefficient of static friction between the tyres and the track is $\mu_s$, then the magnitude of negative lift $F_L$ acting downwards on the car is : (Assume forces on the four tyres are identical and $\mathrm{g}=$ acceleration due to gravity)

$-m\left(g+\frac{v^2}{\mu_s R}\right)$

$m\left(g-\frac{v^2}{\mu_s R}\right)$

$m\left(\frac{v^2}{\mu_s R}-g\right)$

$m\left(\frac{v^2}{\mu_s R}+g\right)$

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A car is moving on a horizontal curved road with radius 50 m. The approximate maximum speed of car will be, if friction between tyres and road is 0.34.

[take g = 10 ms⁻²]

17 ms^–1

13 ms^–1

22.4 ms^–1

3.4 ms^–1

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Concepts Covered - 1

Skidding of Vehicle on a Level Road

$
\begin{aligned}
& \text { Frictional force } \geq \text { Req. centripetal Force } \\
& \mu m g \geq \frac{m v^2}{r} \\
& V_{\text {safe }} \leq \sqrt{\mu r g} \\
& V_{\text {safe }}=\text { Safe vector move } \\
& \mathrm{r}=\text { radius of the curve } \\
& \mu=\text { coefficient of friction }
\end{aligned}
$

- $V_{s a f e}$ is the maximum velocity by which vehicle can turn on a circular path of radius $r$.