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Skidding of Vehicle on a Level Road is considered one of the most asked concept.
5 Questions around this concept.
A vehicle of mass 5000 Kg starts taking a circular turn of radius 10 m. The initial speed of the vehicle on a circular track is 5 $\mathrm{m} / \mathrm{s}$ and it is increasing with the rate of $1 \mathrm{~m} / \mathrm{s}^2$. After how much time the vehicle will be just about to overturn [Assume distance between two vehicle $=4 \mathrm{~m}$, the height of the center of mass of vehicle $=2 \mathrm{~m}, \mathrm{~g}=10 \mathrm{~m} / \mathrm{s}^2$ ]
The maximum speed of a car on a road turn having a radius of curvature 20m, if the coefficient of friction between the tyres and the road is 0.5 will be - (Take $g=10 \mathrm{~m} / \mathrm{s}^2$)
$
\begin{aligned}
& \text { Frictional force } \geq \text { Req. centripetal Force } \\
& \mu m g \geq \frac{m v^2}{r} \\
& V_{\text {safe }} \leq \sqrt{\mu r g} \\
& V_{\text {safe }}=\text { Safe vector move } \\
& \mathrm{r}=\text { radius of the curve } \\
& \mu=\text { coefficient of friction }
\end{aligned}
$
- $V_{s a f e}$ is the maximum velocity by which vehicle can turn on a circular path of radius $r$.
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