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Motion of blocks when connected with string is considered one of the most asked concept.
6 Questions around this concept.
Three blocks are connected as shown on a horizontal frictionless surface , if $m_1=1 \mathrm{~kg}, m_2=8 \mathrm{~kg}, m_3=27 \mathrm{~kg}$ and $T_3=36 \mathrm{~N}, T_2$ will be?
Two blocks connected with a string on smooth horizontal surface
Let accelereration of the blocks be 'a', and Tension in the string be T.
F.B.D of both blocks combined-
$
\begin{aligned}
& \text { From } F_{n e t}=M_{s y s} a \\
& F=\left(m_1+m_2\right) a \\
& \Rightarrow a=\frac{F}{m_1+m_2} \ldots
\end{aligned}
$
F.B.D of block of mass m1-
$\begin{aligned} & \text { From } F_{\text {net }}=M_{\text {sys }} a \\ & T=m_1 a \\ & \text { From equation }(1) \\ & \Rightarrow T=\frac{m_1 F}{m_1+m_2} \ldots(2)\end{aligned}$
Three blocks connected with a string on smooth horizontal surface
Let accelereration of the blocks be 'a', tension in the string between m1 and m2 be T1, and tension between m2 and m3 be T2.
F.B.D of all the blocks combined-
$
\begin{aligned}
& \text { From } F_{\text {net }}=M_{\text {sys }} a \\
& F=\left(m_1+m_2+m_3\right) a \\
& \Rightarrow a=\frac{F}{m_1+m_2+m_3} \ldots
\end{aligned}
$
F.B.D of block m1-
From $F_{\text {net }}=M_{\text {sys }} a$
$T_1=m_1 a$
From equation (1) -
$
\Rightarrow T_1=\frac{m_1 F}{m_1+m_2+m_3} \ldots
$
F.B.D of m3-
$
\begin{aligned}
& \text { From } F_{\text {net }}=M_{\text {sys }} a \\
& F-T_2=m_3 a \\
& \Rightarrow T_2=\frac{\left(m_1+m_2\right) F}{m_1+m_2+m_3} \ldots
\end{aligned}
$
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