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Important Results of Binomial Theorem for any Index - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

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  • Important Results of Binomial Theorem for any Index is considered one the most difficult concept.

  • 47 Questions around this concept.

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If the expansion in powers of x of the function  \dpi{100} \frac{1}{(1-ax)(1-bx)}\,\,is\, \,\,a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+.......,\, then\; a_{n}\; is :

If 0 < x < 1, then the first negative term in the expansion of \dpi{100} (1+x)^{41/7} is:

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Important Results of Binomial Theorem for any Index

Important Results of Binomial Theorem for any  Index
 

\\\text{If the given series is}\\\\\mathrm{(1+x)^n=1+nx+\frac{n(n-1)}{2!}x^2+\frac{n(n-1)(n-2)}{3!}x^3+......+\frac{n(n-1)(n-2).....(n-r+1)}{r!}x^r....}

In the above expansion replace ‘n’ with ‘-n’

\\\\\mathrm{(1+x)^{-n}=1+(-n)x+\frac{(-n)((-n)-1)}{2!}x^2+\frac{(-n)((-n)-1)((-n)-2)}{3!}x^3+......}\\\mathrm{\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;....+\frac{(-n)((-n)-1)((-n)-2).....((-n)-r+1)}{r!}x^r.........\infty}

\Rightarrow \mathrm{(1+x)^{-n}=1-nx+\frac{n(n+1)}{2!}x^2-\frac{n(n+1)(n+2)}{3!}x^3+......}\\\mathrm{\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;....+(-1)^r\frac{n(n+1)(n+2).....(n+r-1)}{r!}x^r.........\infty}

If -n is a negative integer (so that n is a positive integer), then we can re-write this expression as 

=1-^{n} C_{1} x+^{n+1} C_{2} x^{2}-^{n+2} C_{3} x^{3}+\cdots+^{n+r-1} C_{r}(-x)^{r}+\cdots 

 

Now replace ‘x’ with ‘-x’ and ‘n’ with ‘-n’ in the binomial expansion (1 + x)n.

\\(1-x)^{-n}=1+ n x+\frac{n(n+1)}{2 !} x^{2}+\frac{n(n+1)(n+2)}{3 !} x^{3}+\cdots \\ +\frac{n(n+1)(n+2) \cdots(n+r-1)}{r !} x^{r}+\cdots\\\\\text{If -n is a negative integer (so that n is a positive integer), then we can re-write this expression as } \\\\=1+^{n} C_{1} x+^{n+1} C_{2} x^{2}+^{n+2} C_{3} x^{3}+\cdots+^{n+r-1} C_{r}(x)^{r}+\cdots

 

Important Note:

The coefficient of xr in (1 - x)-n, (when n is a natural number) is n+r-1Cr
 

Some Important Binomial Expansion

\\1.\;\;(1+x)^{-1}=1-x+x^{2}-x^{3}+\cdots\\2.\;\;(1-x)^{-1}=1+x+x^{2}+x^{3}+\cdots\\\3.\;\;(1+x)^{-2}=1-2 x+3 x^{2}-4 x^{3}+\cdots\\4.\;\;(1-x)^{-2}=1+2 x+3 x^{2}+4 x^{3}+\cdots

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Important Results of Binomial Theorem for any Index

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