Hello Aspirant,

The jee mains eligibility criteria are as follows -

• Candidates should pass from any recognised board or University.
• Candidates should opt for physics chemistry and mathematics as mandatory subjects in their class 12th.
• Candidates should secure a minimum of 75 percentage in their class 12th.

To know about

Hello Aspirant,

As per my view you need to spent some time on every question you solve in jee advanced during your preparation because this exams tests your mental ability along efficiency. The speed factor is also there but it comes later when your thinking ability is at its peak.

JEE Advanced 2024 was held on Sunday, May 26, 2024. The exam had two papers: Paper 1 from 9 AM to 12 PM and Paper 2 from 2:30 PM to 5:30 PM. Both papers are important and done on computers. The results came out on June 9, 2024. For next

Hello Aspirant,

There are many factors such as number of candidates appearing in the examination, previous year cutoffs and difficulty level of the paper.

But as per my view you should be able to get atleast lower iits like IIT Mandi, IIT Jodhpur, IIT Jammu. But yes in these IITs

Hello Aspirant,

In my view there is no point in joining IIT considering you as a general category candidate if your rank is 20000 . You may chances to get the lowest branches but as per my view it's better to opt for nits if you have secured a good

With a preparatory SC rank of 1612 in JEE Advanced, you have a chance to secure admission into IITs offering preparatory courses. These courses are designed for candidates who fall just short of the general cutoff but show potential. Your admission will depend on seat availability and the IIT's specific

Given your EAMCET rank of 1803, JEE Mains OBC rank of 9600, and JEE Advanced OBC rank of 8595, your best option for Computer Science Engineering (CSE) would likely be through EAMCET. With your rank, you could secure admission to top engineering colleges in Andhra Pradesh or Telangana, especially in