Hello! Saikat

Your percentile is awesome.Your rank will be enough to get NITs.I can give you rough idea about your rank under general quota  using this formula:{100-percentile score}×145386/100.where 145386 total number of aspirants that apoera in 1st phase of jee mains paper 2 examination.Your rank will be around 1.7k.Usually with

Hello Richa,

 I would like to suggest you to give second attempt so that you can improve your score.

Use this formula to predict the rank by your percentile.

Rank Formula = (100 - your total score) X 145386 /100.

On the basis of the rank only the cutoff for

Hello Kajal

To give 2019 advance first you have to be eligible for JEE mains 2019 and then you have to crack JEE mains paper then only then you are eligible for JEE advance.

JEE mains eligibility Criteria :

• There is no age limit to be eligible for JEE Main

Hello,

I would like to tell you that the Diploma holders are not permitted to take JEE Mains as Diploma program is for 3 years.

There are many other eligibility criteria for JEE like:

• For Btech courses via JEE Main, candidates need to be from Scienece stream only with PCM

• The mode of the exam is computer based online mode only.
• Also the registrations will be opened tentatively from first week of may to second week of may.
• both for paper

Hello Sugumaran

45 percentile is very low score and with this score you may be not able to qualify for jee advanced.

So prepare for next attempt and score atleast 98-100 percentile marks. You can qualify in 85-90 percentile also but I think if you are capable of getting 98+

Hii

First thing you need is to have paitance. Since the exam is approaching the level of exam will increase. You need not to worry about it. Practise more is the only thing which will help you in test. Practise as many mocks as you can. Do meditation daily and

Hi Aditya Kumar !

Congratulations ! You cleared JEE MAINS examination . So, you must have clear concepts of PCM chapters . Go through previous year questions . This will help you a lot . If you get stucked in any problem then watch free video lectures available on YouTube