Andhra Pradesh Engineering Common Entrance Test
Hi Aspirant,
According to the previous trends and your rank you can get allotted to JNTUA KALIKIRI and even get CSE.
You can refer to the link below:-
https://www.careers360.com/colleges/jntua-college-of-engineering-kalikiri/cut-off
For more AP EAMCET colleges you can use college predictor:-
AP EAMCET College Predictor 2022 - Predict Colleges based on your Rank (careers360.com)
Hey,
Admission to B.TECH./B.PHARMA. will be based on the performance in V-SAT conducted by the university or based on JEE Mains/ Advanced AP EAMCET/ TS EAMCET. Eligibility criteria:- Higher Secondary Examination Qualified (12th) with PCM. Minimum marks of 60% marks secured in the final examination. The applicant should be born on or after 1st July 1998. At least 25% aggregate marks out of total. For further information visit the link given below:-
https://engineering.careers360.com/articles/ap-ecet-result
Thank You!
Dear aspirant hope you are doing well. It's difficult to predict because cut keep changing every year depends on various factors.
1. No of seat available.
2. Difficulty level of exam.
3. No of student appear in exam.
As your rank is 276 in Ap eamcet exam.your rank would lies in between 85 – 89 . You can check out the same at our site. Link is given below..
https://engineering.careers360.com/articles/ap-eamcet-marks-vs-rank/amp
JNTU Kakinada cut off 2021 based on AP-EAMCET 2020 for BTech courses for general category students is given below.
JNTU Kakinada B.Tech Cut Off 2021.
SpecializationCut off Rank
You can also use Andhrapradesh Eamcet college predictor tool to know the list of college, you have chances of getting admission according to your score, category, state and rank. Link is given below.
https://www.careers360.com/ap-eamcet-college-predictor
Hope it's helpful thank you
Hello,
To predict the colleges where you might have chances of getting seat in based on your performance in the TS-EAMCET 2022, kindly check out the Careers 360's college predictor. Here is a link to it -
https://www.careers360.com/ts-eamcet-college-predictor?utm_source=qna&utm_medium=ini-cet_cp
------ With the college predictor you get to know about the colleges where you have good chance, medium chance and tough chances of getting seat. Also you will get to know actual cut offs.
The chances provided are based on minute details such as Rank, Caste, Homestate, gender etc.
I hope you find the answer helpful
Thank you
Hello Aspirant,
As per previous year cutoff for CSE branch it was 1000 so you will get a chance to admission in JNTUCEK with CSE branch.
Go through this link to get information about cutoff of JNTUCEK :
https://www.careers360.com/colleges/jawaharlal-nehru-technological-university-college-of-engineering-kakinada/cut-off
Use this link to predict colleges based on your rank ;
https://www.careers360.com/ap-eamcet-college-predictor?utm_source=qna&utm_medium=ini-cet_cp
Hope this information helps you.
Best Wishes!
Hello aspirant,
With the above mentioned rank in AP EAMCET and according to the previous year Cutoff, you have good chances of getting EEE/ECE in JNTU kakinada. According to teh last year's AP EAMCET Cutoff, you also have a chance of getting Chemical and Civil engineering branch in JNTU Kakinada. The previous year Cutoff required to get ECE/EEE seat in JNTU Kakinada are around 2000 in AP EAMCET.
Further, to know more about the AP EAMCET cutoff for JNTU Kakinada, you can follow the below mentioned link to know more : https://engineering.careers360.com/articles/ap-eamcet-cutoff
Further, to know more about your admission chances in other colleges, you can follow the below mentioned College predictor link to know more about it : https://www.careers360.com/ap-eamcet-college-predictor
I hope that this will help.
hello aspirant,
YES, you can get FEES Reimbursement providing if you are a resident from Andhra pradesh.
Further, the eligibility criteria for getting full fees reimbursement in AP through APEAMCET is as follows : Full Fee Reimbursement for students of ranks below 10000 & Rs 35000 Reimbursement for all ranks above 10000, Govt of AP Final Decision. Full/Complete Fee Reimbursement for the students of ranks below 10000.
hello sridhar !
As per your query , if you want engineering colleges you need to qualify ap eamcet with minimum 25% marks or univeristy entrance test based on the college you selected.
some of the best engineering colleges are
1. S R K R engineering college , bhimavaram .
2. G Pulla Reddy engineering college , kurnool.
3. Gayatri vidhya prashad college of engineering , vizag.
4.Andhra University college of engineering , visakhapatanam.
5. Audisankara college of engineering and technology , gudur
6. K L University , guntur.
for more information follow the below links
https://engineering.careers360.com/colleges/ranking/top-engineering-colleges-in-andhra-pradesh
https://engineering.careers360.com/colleges/ranking/top-engineering-colleges-in-andhra-pradesh-accepting-ap-eamcet-score
Hi Aspirant!
APECET is one of the topmost entrance exam for lateral entry admissions in the colleges of Andhra Pradesh. The exam result is valid in all the colleges of Andhra Pradesh.
>> Other than this exam there are various lateral entry exams conducted by different colleges of Andhra Pradesh such as VUCET by Vignan's University, etc.
>> You can check out the colleges in which you wish to take admission and then check out the entrance exams conducted by them for lateral entry admissions.
Thankyou!
Last year a candidate with rank 9060 secured admission to Electronics and Communication Engineering in Andhra University College of Engineering. Considering the cut off you need to secure a rank under 9000 to have decent chances to get seat in Andhra University College of Engineering in Electronics and Communication Engineering. Cut off is subjected to change it may increase or decrease depending on the total number of candidates applied, difficulty level of examination and total number of seats available etc. To check the cut off use the link given below
https://eapcet-apsche.aptonline.in/EAPCET/collegeWiseAllotedReport.xls;jsessionid=uaoG3N-qbd24qpbMCZoTLxqB
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