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Various types of speeds of ideal gases is considered one of the most asked concept.
64 Questions around this concept.
At room temperature, a diatomic gas is found to have an r.m.s. speed of 1930 ms-1. The gas is :
Which of the following statements is true for gas?
(i) For a certain temperature, the average speed is always greater than the most probable speed.
(ii) Ratio of Vrms: Vav: Vmp is: 1.77: 1.6: 1.41
The root mean square velocity of molecules of gas is
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Molecules of types 1,2, and 3 having molar masses $m_1>m_2>m_3$ make up a gas mixture. The gases' rms speed is expressed as vrms. Which of these statements is correct?
Choose the correct relation b/w $V_{r m s}, V_{\text {avg }}, V_{m p}$
If two gases of molecular weights M1 and M2 are at the same pressure and temperature, ratio of their r.m.s. speed will be
Consider the following statements for air molecules in an airtight container.
(I) the average speed of molecules is larger than root mean square speed
(II) mean free path of molecules is larger than the mean distance between molecules
(III) mean free path of molecules increases with temperature
(IV) the rms speed of nitrogen molecule is smaller than oxygen molecule
The true statements are:
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At room temperature the r.m.s. velocity of the molecules of a certain diatomic gas is found to be 1930 m/sec. The gas is :
Maxwell distribution curve at a particular temperature shows that
ie. $v_{m s}=\sqrt{\frac{v_1^2+v_2^2+v_3^2+v_4^2+\ldots}{N}}=\sqrt{\bar{v}^2}$
1. As the Pressure due to an ideal gas is given as
$
\begin{aligned}
& P=\frac{1}{3} \rho v_{r m s}^2 \\
\Rightarrow & v_{r m s}=\sqrt{\frac{3 P}{\rho}}=\sqrt{\frac{3 P V}{\text { Mass of gas }}}=\sqrt{\frac{3 R T}{M}}=\sqrt{\frac{3 k T}{m}} \\
& \text { Where } \\
\mathrm{R}= & \text { Universal gas constant } \\
\mathrm{M}= & \text { molar mass } \\
\mathrm{P}= & \text { pressure due to gas } \\
\rho & =\text { density }
\end{aligned}
$
2. $v_{r m s} \alpha \quad \sqrt{T}$ I.e With the rise in temperature, rms speed of gas molecules increases.
3. $v_{r m s} \alpha \frac{1}{\sqrt{M}}$ I.e With the increase in molecular weight, $r$ ss speed of the gas molecule decreases.
4. The rms speed of gas molecules does not depend on the pressure of the gas (if the temperature remains constant)
$
v_{m p s}=\sqrt{\frac{2 P}{\rho}}=\sqrt{\frac{2 R T}{M}}=\sqrt{\frac{2 k T}{m}}
$
- Average speed-lt is the arithmetic mean of the speeds of molecules in a gas at a given temperature.
$
v_{\text {avg }}=\frac{v_1+v_2+v_3+v_4+\ldots}{N}
$
and according to the kinetic theory of gases
$
v_{a v g}=\sqrt{\frac{8 P}{\pi \rho}}=\sqrt{\frac{8}{\pi} \frac{R T}{M}}=\sqrt{\frac{8}{\pi} \frac{k T}{m}}
$
- The relation between RMS speed, average speed, and most probable speed
$
V_{r m s}>V_{a v g}>V_{m p s}
$
Maxwell’s Law -
The $v_{r m s}$ (Root mean square velocity) gives us a general idea of molecular speeds in a gas at a given temperature. So, it doesn't mean that the speed of each molecule is $v_{r m s}$.
Many of the molecules have speed less than $v_{r m s}$ and many have speeds greater than $v_{r m s}$. So, Maxwell derived an equation that describes the distribution of molecules in different speeds as -
$
\mathrm{dN}=4 \pi \mathrm{~N}\left(\frac{\mathrm{~m}}{2 \pi \mathrm{kT}}\right)^{3 / 2} \mathrm{v}^2 \mathrm{e}^{-\frac{\mathrm{mv}^2}{2 \mathrm{kT}}} \mathrm{dv}
$
where, $d N=$ Number of molecules with speeds between $v$ and $v+d v$
So, from this formula, you have to remember a few key points -
1. $\frac{d N}{d v} \propto N$
2. $\frac{d N}{d v} \propto v^2$
Conclusions from this graph -
1. This graph is between number of molecules at a particular speed and speed of these molecules.
2. You can observe that the $\frac{d N}{d v}$ is maximum at most probable speed.
3. This graph also represent that $v_{r m s}>v_{a v}>v_{m p}$.
4. This curve is asymmetric curve.
5. From this curve we can calculate number of molecules corresponds to that velocity range by calculating area bonded by this curve with speed axis.
Effect of temperature on velocity distribution :
With rising of temperature, the curve starts shifting right side and become broader as shown as -
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