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Sum of n-term of a GP is considered one of the most asked concept.
31 Questions around this concept.
Find the sum of nth terms of the positive perfect square integers, where, , whose nth term is .
Let . be a G. P. of increasing positive numbers. Let the sum of its and terms be 2 and the product of its and terms be . Then is equal to
If the sum and product of four positive consecutive terms of a G.P., are 126 and 1296 , respectively,
then the sum of common ratios of all such GPs is
Sum of n-term of a GP
Let Sn be the sum of n terms of the G.P. with the first term ‘a’ and common ratio ‘r’. Then
The above formula does not hold for r = 1
For r = 1, each of the n terms is equal to a, and thus the sum of n terms of the G.P. is .
Sum of an infinite GP
If a is the first term and r is the common ratio of a G.P. Then,
Let, - 1 < r < 1, i.e. | r | < 1, then
[as this is infinite G.P., so n tends to infinity]
is the sum to infinite terms of the G.P.
Note: If r ≥ 1, then the sum of an infinite G.P. tends to infinity.
Application of GP
To write a non-terminating repeating number in p/q form:
Example:
The value of 0.358585858585..........
Application of GP
The sum of n-term of the series is
The sum of n-term of the series is
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Mathematics for Joint Entrance Examination JEE (Advanced) : Algebra
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Mathematics for Joint Entrance Examination JEE (Advanced) : Algebra
Page No. : 5.15
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Mathematics for Joint Entrance Examination JEE (Advanced) : Algebra
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