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Arithmetic Mean in AP - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Arithmetic Mean is considered one the most difficult concept.

  • 29 Questions around this concept.

Solve by difficulty

If 1, \log_{9}\left ( 3^{1-x}+2 \right ), \log_{3}\left ( 4.3^{x}-1 \right ) are in A.P. then x equals:

 Let G be the geometric mean of two positive numbers a and b, and M be the arithmetic mean of  \frac{1}{a}  and \frac{1}{b}

if \frac{1}{M}:G  is 4:5 then a:b can be:

For any three positive real numbers a, b and c, 9(25a2+b2)+25(c2−3ac)=15b(3a+c). Then:

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The number of ways in which 5 boys and 3 girls can be seated on a round table if a particular boy $\mathrm{B}_1$ and a particular girl $\mathrm{G}_1$ never sit adjacent to each other, is :

If 14 AM's are inserted between 1 and 31 then the common difference between them is?

Mean of 100 observations is 45. It was later found that two observations 19 and 31 were incorrectly recorded as 91 and 13. The correct mean is:

AMs are inserted between 2 and 38. If the third AM is 14, then n is equal to

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The average of n numbers $x_1, x_2, x_3, \ldots \ldots x_n$ is $M$. If $x_n$ is replaced by $x^1$ then new average is

5 GMs and 5 AMs are inserted between 1 and 64. If P is the product of these 5 GMs and S is the sum of these 5 AMs, then P + S equals

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Concepts Covered - 2

Arithmetic Mean

Arithmetic Mean
If three terms are in $A P$, then the middle term is called the Arithmetic Mean (A.M.) of the other two numbers. So if a, b and c are in A.P., then $b$ is $A M$ of a and $c$. If $a_1, a_2, a_3, \ldots \ldots, a_n$ are $n$ positive numbers, then the Arithmetic Mean of these numbers is given by

$
A=\frac{a_1+a_2+a_3+\ldots \ldots+a_n}{n}
$
Insertion of $\mathbf{n}$-Arithmetic Mean Between $\mathbf{a}$ and $\mathbf{b}$
If $\mathrm{A}_1, \mathrm{~A}_2, \mathrm{~A}_3 \ldots, \mathrm{~A}_{\mathrm{n}}$ are n arithmetic mean between two numbers a and b, then, $a, \mathrm{~A}_1, \mathrm{~A}_2, \mathrm{~A}_3 \ldots, \mathrm{~A}_{\mathrm{n}}, b$ is an $\mathrm{A}. \mathrm{P}$.
Let d be the common difference of this A.P. Clearly, this A.P. contains $\mathrm{n}+2$ terms.

$
\begin{aligned}
& \therefore b=(n+2)^{t h} \text { term } \\
& \Rightarrow b=a+((n+2)-1) d=a+(n+1) d \\
& \Rightarrow d=\frac{b-a}{n+1}
\end{aligned}
$
Now,

$
\begin{aligned}
& A_1=a+d=\left(a+\frac{b-a}{n+1}\right) \\
& A_2=a+2 d=\left(a+\frac{2(b-a)}{n+1}\right) \\
& \ldots \\
& \cdots \\
& A_n=a+n d=\left(a+n\left(\frac{b-a}{n+1}\right)\right)
\end{aligned}
$
 

Important Property of AM

The sum of the n arithmetic mean between two numbers is n times the single A.M. between them.
Proof:
Let $\mathrm{A}_1, \mathrm{~A}_2, \mathrm{~A}_3 \ldots, \mathrm{~A}_{\mathrm{n}}$ be n arithmetic mean of two numbers a and b.
Then, $a, \mathrm{~A}_1, \mathrm{~A}_2, \mathrm{~A}_3 \ldots, \mathrm{~A}_{\mathrm{n}}, b$ is an A.P. with common difference $\frac{b-a}{n+1}$.

Now,

$
\begin{aligned}
& \mathrm{A}_1+\mathrm{A}_2+\mathrm{A}_3+\ldots \ldots+\mathrm{A}_{\mathrm{n}} \\
& =\frac{\mathrm{n}}{2}\left[\mathrm{~A}_1+\mathrm{A}_{\mathrm{n}}\right] \\
& =\frac{\mathrm{n}}{2}[a+b] \\
& {\left[\because a, \mathrm{~A}_1, \mathrm{~A}_2, \ldots, \mathrm{~A}_{\mathrm{n}}, \mathrm{~b} \text { is an A.P., } \therefore a+b=A_1+A_n\right]} \\
& =\mathrm{n}\left(\frac{a+b}{2}\right) \\
& =\mathrm{n} \times(\text { A.M. between } a \text { and } b)
\end{aligned}
$

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Arithmetic Mean
Important Property of AM

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Reference Books

Arithmetic Mean

Mathematics for Joint Entrance Examination JEE (Advanced) : Algebra

Page No. : 5.8

Line : Last Line

Important Property of AM

Mathematics for Joint Entrance Examination JEE (Advanced) : Algebra

Page No. : 5.8

Line : Last Line

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