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Enthalpy Of Combustion, Enthalpy Of Dissociation, Atomisation And Phase Change is considered one of the most asked concept.
31 Questions around this concept.
A sample of ice at is heated until it completely vaporizes into steam at .Calculate the total heat transfer during this process, including the heat required for fusion and vaporization. Additionally, determine the change in entropy during each phase transition and the total change in entropy for the entire process. Given the specific heat capacity of ice is , the specific heat capacity of water is , the heat of fusion of ice is , the heat of vaporization of water is , and the molar gas constant is .
The standard enthalpy of formation (fHo298) for methane, CH4 is -74.9 kJ mol-1. In order to calculate the average energy given out in the formation of a C - H bond from this it is necessary to know which one of the following?
Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules?
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The bond dissociation energy is highest for
The correct order of bond enthalpy $\left(\mathrm{kJmol}^{-1}\right)$ is :
Calculate the change in enthalpy when of water at is converted to steam at The heat of
vaporization of water is
Calculate the change in entropy $(\Delta S)$ when 100 g of liquid water at $100^{\circ} \mathrm{C}$ is converted into steam at $100^{\circ} \mathrm{C}$. Given the heat of vaporization $\left(\Delta \mathrm{H}_{\text {vap }}\right)$ of water is $40.79 \mathrm{~kJ} / \mathrm{mol}$.
A sample of ice at is heated until it becomes steam at .Calculate the total heat required to first raise the temperature of the ice to its melting point and then convert it to steam. Given the specific heat capacity of ice is , the heat of fusion of ice is ,the specific heat capacity of water is ,and the heat of vaporization of water is .
Consider a reversible heat engine operating between two reservoirs at temperatures $T_1$ and $\mathrm{T}_2\left(\mathrm{~T}_1>\mathrm{T}_2\right)_{\text {.The engine absorbs }} \mathrm{Q}_1$ heat from the reservoir at temperature $\mathrm{T}_1$ and rejects $Q_2$ heat to the reservoir at temperature $T_2$. Show that the efficiency $(\eta)$ of the heat engine can be expressed as:
$$
\eta=1-\frac{T_2}{T_1}
$$
The standard enthalpy of formation of . it the enthalpy of formation of form atoms is . The average bond enthalpy of bond in is
Heat of Combustion
1. It is, changes in enthalpy when one mole of a substance is completely oxidized or combusted or burnt.
2. $\Delta \mathrm{H}$ is - ve here as heat is always evolved here that is, exothermic process.
3. Heat of combustion is useful in calculating the calorific value of food and fuels.
4. It is also useful in confirming the structure of organic molecules having C, H, O, N, etc.
5. Enthalpy change by combustion of 1 gm solid or 1 gm liquid or 1 cc gas is called calorific value.
calorific value $=\frac{\text { Heat of combustion }}{\text { Molecular wt. }}$
$\Delta \mathrm{H}($ heat of reaction $)=-\Sigma \Delta \mathrm{H}_{\mathrm{P}}^{\circ}-\Sigma \mathrm{H}_{\mathrm{R}}^{\circ}$
Enthalpy of Dissociation or Ionization
It is defined as, "The quantity of heat absorbed when one mole of a substance is completely dissociated into its ions". Example,
$\mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{H}^{+}+\mathrm{OH}^{-} \quad \Delta \mathrm{H}=13.7 \mathrm{Kcal}$
Heat of Atomization
It is the enthalpy change (heat required) when bonds of one mole of a substance are broken down completely to obtain atoms in the gaseous phase (isolated) or it is the enthalpy change when one mole of atoms in the gas phase is formed from the corresponding element in its standard state. In case of diatomic molecules, it is also called bond dissociation enthalpy.
It is denoted by $\Delta \mathrm{H}_{\mathrm{a}}$ or $\Delta \mathrm{H}^{\circ}$.
Example,
$
\begin{aligned}
& \mathrm{H}_2(\mathrm{~g}) \rightarrow 2 \mathrm{H}(\mathrm{~g})-435 \mathrm{~kJ} \\
& \Delta \mathrm{H}=+435 \mathrm{~kJ} / \mathrm{mol} \\
& \mathrm{CH}_4(\mathrm{~g}) \rightarrow \mathrm{C}(\mathrm{~g})+4 \mathrm{H}(\mathrm{~g})+1665 \mathrm{~kJ} \\
& \Delta \mathrm{H}=+1665 \mathrm{~kJ} / \mathrm{mol}
\end{aligned}
$
Phase Transition and Transition Energy
$\begin{aligned} & \text { Example, } \\ & \qquad \mathrm{C} \text { (diamond) } \rightarrow \mathrm{C} \text { (amorphous) } \\ & \Delta \mathrm{H}=3.3 \mathrm{Kcal}\end{aligned}$
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