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    JEE Main Paper 1 Syllabus 2026 for Maths, Physics, Chemistry

    Introduction To Heat, Internal Energy And Work - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:35 AM | #JEE Main

    Quick Facts

    • 32 Questions around this concept.

    Solve by difficulty

    A refrigerator operates on a Carnot cycle between two reservoirs at temperatures \mathrm{T_{\text {hot }}=300 \mathrm{~K} \, \, and\, \, T_{\text {cold }}=200 \mathrm{~K}}. Calculate the coefficient of performance (COP) of the refrigerator.
     

    The $\delta \mathrm{G}$ in the process of melting of ice at -15° C is

    The pressure-volume work for an ideal gas can be calculated by using the expression

    $w=-\int_{v_i}^{v_f} P_{e x} d V$

    The work can also be calculated from the pV - plot by using the area under the curve within the specified limits. When an ideal gas is compressed (a) reversibly or (b) irreversibly from Vi to Vf, choose the correct option.
     

    Internal energy of an ideal gas is a function of

    A gas in a piston undergoes a process in which it release 400 J of heat and does 300 J does of work on its surroundings. Calculate the change in internal energy for this process.

    A gas undergoes an isobaric expansion at a temperature of 400 K, absorbing 500 J of heat during this process. If the work done by the gas is 300 J, calculate the change in internal energy.

    A system undergoes a process in which it absorbs 200 J of heat and does 150 J of work on its surroundings. Calculate the change in internal energy for this process.

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    A gas confined within a piston-cylinder arrangement undergoes a thermodynamic process. Initially, the gas has an internal energy of 1500 J, and the system performs 400 J of work on its surroundings while releasing 300 J of heat. Determine the final internal energy of the gas.

    A gas is subjected to a process during which it absorbs 1200 J of heat and performs 900 J of work on the surroundings. If the initial internal energy of the gas is 2500 J, calculate its final internal energy.

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    A gas undergoes a reversible isothermal compression from an initial volume of $0.04 \mathrm{~m}^3$ to a final volume of $0.02 \mathrm{~m}^3$ at a temperature of 400 K . If 500 J of heat is released to the surroundings during the process, calculate the change in internal energy of the gas.

    Concepts Covered - 2

    Heat And Work

    Heat 

    Heat is the energy transfer due to the difference in temperature. Heat is a form of energy which the system can exchange with the surroundings if they are at different temperatures. The heat flows from higher temperature to lower temperature. 

    Heat is expressed as 'q' 

    Heat absorbed by the system = +q 

    Heat evolved by the system = - q

     

    Work 

    It is the energy transfer due to the difference in pressure that is, the mode of energy transfer.


    Types of work 

    (i) Mechanical Work (Pressure volume work) = Force x Displacement 

    (ii) Electrical Work = Potential difference x charge flow  , VQ = EnF

    (iii) Expansion Work $=\mathrm{P} \times \Delta \mathrm{V}=-\mathrm{P}_{\text {ext. }}\left[\mathrm{V}_2-\mathrm{V}_1\right]$

    $\mathrm{P}=$ external pressure And $\Delta \mathrm{V}=$ increase or decrease in volume.

    (iv) Gravitational Work = mgh 

    Here m = mass of body, 

    g = acceleration due to gravity 

    h = height moved.

     

    Units: dyne cm or erg (C.G.S.) 

               Newton meter (joule) 

    (i) If the gas expands, [V2> V1] and work is done by the system and W is negative. 

    (ii) If the gas [V2 < V1] and work is done on the system and W is positive.


    Different Types of Works and the Formulas 

    (i) Work done in reversible isothermal process

    $\begin{aligned} & \mathrm{W}=-2.303 \mathrm{nRT} \log _{10} \frac{\mathrm{~V}_2}{\mathrm{~V}_1} \\ & \mathrm{~W}=-2.303 \mathrm{nRT} \log _{10} \frac{\mathrm{P}_1}{\mathrm{P}_2}\end{aligned}$

    (ii) Work done in irreversible isothermal process

    Work $=-\mathrm{P}_{\text {ext. }}\left(\mathrm{V}_2-\mathrm{V}_1\right)$
    That is, Work $=-\mathrm{P} \times \Delta \mathrm{V}$

    Internal Energy

    Internal Energy or Intrinsic Energy 

    The energy stored within a substance is called its internal energy. The absolute value of internal energy cannot be determined. 

    Or

    It is the total energy of a substance depending upon its chemical nature, temperature, pressure, and volume, amount of substrate. It does not depend upon path in which the final state is achieved.

    \begin{array}{l}{\mathrm{E}=\mathrm{E}_{\mathrm{t}}+\mathrm{E}_{\mathrm{r}}+\mathrm{E}_{\mathrm{v}}+\mathrm{E}_{\mathrm{e}}+\mathrm{E}_{\mathrm{n}}+\mathrm{E}_{\mathrm{PE}}+\mathrm{E}_{\mathrm{B}}} \\ {\mathrm{E}_{\mathrm{t}}=\text { Transitional energy }} \\ {\mathrm{E}_{\mathrm{r}}=\text { Rotational energy }} \\ {\mathrm{E}_{\mathrm{PE}}=\text { Potential energy }} \\ {\mathrm{E}_{\mathrm{B}}=\text { Bond energy }}\end{array}

    The exact measurement of it is not possible so it is determined as  \mathrm {\Delta E} as follows:

    \\ \Delta \mathrm{E}=\Sigma \mathrm{E}_{\mathrm{p}}-\Sigma \mathrm{E}_{\mathrm{R}} \\ {\Delta \mathrm{E}=\mathrm{E}_{\mathrm{f}}-\mathrm{E}_{\mathrm{i}}} \\ {\text {Here } \mathrm{E}_{\mathrm{f}}=\text { final internal energy }} \\ {\mathrm{Ei}=\text { Initial internal energy }} \\ {\mathrm{Ep}=\text { Internal energy of products }} \\ {\mathrm{Er}=\text { Internal energy of reactants }}

     

    Facts about Internal Energy 

    • It is an extensive property.

    • Internal energy is a state property. 

    • The change in internal energy does not depend on the path by which the final state is reached.

    • Internal energy for an ideal gas is a function of temperature only so when the temperature is kept constant \mathrm{\Delta E}  is zero for an ideal gas.

    \\\mathrm{E\propto T} \\ \\\mathrm{\Delta E = nC_v\Delta T [\ C_v \textup{ is the heat capacity at constant volume}]}

    • For a cyclic process \Delta \mathrm{E}  is zero. (E = state function), \mathrm { E \propto T}

    • For an ideal gas, it is totally kinetic energy as there is no molecular interaction. 

    • Internal energy for an ideal gas is a function of temperature only hence, when the temperature is kept constant it is zero.

    • At constant volume (Isochoric) \mathrm {Q_v= \Delta E}    

    • For exothermic process, \mathrm{\Delta E} is negative as but For endothermic process \mathrm{\Delta E} is positive as .

    • It is determined by using a Bomb calorimeter of the system.

    \begin{array}{l}{\Delta \mathrm{E}=\frac{\mathrm{Z} \times \Delta \mathrm{T} \times \mathrm{m}}{\mathrm{W}}} \\ {\mathrm{Z}=\text { Heat capacity of Bomb calorimeter }} \\ {\Delta \mathrm{T}=\text { Rise in temperature }} \\ {\mathrm{w}=\text { Weight of substrate (amount) }} \\ {\mathrm{m}=\text { Molar mass of substrate }}\end{array}

    Study it with Videos

    Heat And Work
    Internal Energy

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