JEE Main 2025 Syllabus PDF (Out) - Download Subject-Wise Detailed Syllabus Here

Specific Heat Of A Gas - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Specific heat of a gas is considered one the most difficult concept.

  • 28 Questions around this concept.

Solve by difficulty

 C_{p} and C_{v} are specific heats at constant pressure and constant volume respectively. It is observed that

C_{p}-C_{v}=a  for hydrogen gas

C_{p}-C_{v}=b  for nitrogen gas

The correct relation between a and b is :

The specific heats C_{p} and  C_{v} of a gas of diatomic molecules A are given ( in units of J\:mol^{-1} ) by 29 and 22  respectively. Another gas of diatomic molecule B has the corresponding values of 30 and 21 respectively. If they are treated as ideal gases then :

Two cylinders A and B fitted with pistons contain equal amounts of an ideal diatomic gas at 300 \mathrm{~K}. The piston \mathrm{A} is free to move, while that of \mathrm{B} is held fixed. The same amount of heat is given to the gas in each cylinder. If the rise in temperature of the gas in \mathrm{A} is \mathrm{30 \mathrm{~K}}, then the rise in temperature of the gas in \mathrm{ \mathrm{B}} is.

Two moles of a monatomic gas are mixed with three moles of a diatomic gas. The molar-specific heat of the mixture at constant volume is:

The molar capacity of a mono-atomic gas if it does a work of -Q / 2 unit when supplied a heat of Q  units is,

The given figure has two paths from state A to state B of a thermodynamics process The ratio of molar heat capacity in process 1 & 2 is

The pressure of a monoatomic gas increases linearly from4 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2} to 8 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2} when its volume increases from 0.2 \mathrm{~m}^{3} to \mathrm{~m}^{3} .Calculate

Question: molar heat capacity of the gas  \mathrm{[R=8.31 \mathrm{~J} / \mathrm{mol} \, \mathrm{k}]}

UPES B.Tech Admissions 2025

Ranked #42 among Engineering colleges in India by NIRF | Highest CTC 50 LPA , 100% Placements

Amrita University B.Tech 2025

Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships

The molar heat capacity of a diatomic gas, if it does a work of Q/4, when Q amount of heat is supplied to it, is

600 \mathrm{~J} of heat is added to a monatomic gas in a process in which the gas performs a work of 150 \mathrm{~J}.The molar heat capacity for the process is

JEE Main Exam's High Scoring Chapters and Topics
This free eBook covers JEE Main important chapters & topics to study just 40% of the syllabus and score up to 100% marks in the examination.
Download EBook

 An ideal gas is taken through a cycle \mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{A} as shown in figure. If the heat supplied in the cycle is 5 \mathrm{~J}, then work done by the gas in the process \mathrm{C} \rightarrow \mathrm{A} is

Concepts Covered - 1

Specific heat of a gas

Specific heat - The specific heat is the amount of heat per unit mass required to raise the temperature by one Kelvin.

Now for gases we have several types of specific heat, but here we will discuss basically two types of specific heat - 

  1. Specific heat at constant volume(cv) -It is defined as the quantity of heat required to raise the temperature of unit mass of gas through 1°C or 1 Kelvin at constant volume.

           It is given as -    c_{v}=\frac{(\Delta Q)_{V}}{m \Delta T}  

If 1 mole of gas is placed at the place of unit mass is considered, then this specific heat of gas is called molar specific heat at constant volume and is represented by Cv (Here C is capital)

So, for molar specific heat - 

                                 C_{V}=M c_{V}=\frac{M(\Delta Q)_{V}}{m \Delta T}=\frac{1}{\mu} \frac{(\Delta Q)_{V}}{\Delta T} \quad\left[\text { As } \mu=\frac{m}{M}\right] 

 

2. Specific heat at constant pressure (cp) -It is defined as the quantity of heat required to raise the temperature of unit mass of gas through 1°C or 1 Kelvin at constant pressure.

           It is given as -    c_{p}=\frac{(\Delta Q)_{p}}{m \Delta T}  

If 1 mole of gas is placed at the place of unit mass is considered, then this specific heat of gas is called molar specific heat at constant pressure and is represented by Cp (Here C is capital)

So, for molar specific heat at constant pressure - 

                                 C_{p}=M c_{p}=\frac{M(\Delta Q)_{p}}{m \Delta T}=\frac{1}{\mu} \frac{(\Delta Q)_{p}}{\Delta T} \quad\left[\text { As } \mu=\frac{m}{M}\right] 

 

 

 

Study it with Videos

Specific heat of a gas

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Books

Reference Books

Specific heat of a gas

Physics Part II Textbook for Class XI

Page No. : 330

Line : 13

E-books & Sample Papers

Get Answer to all your questions

Back to top