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Series LR Circuit - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Series LR circuit is considered one the most difficult concept.

  • 90 Questions around this concept.

Solve by difficulty

The given phasor diagram represent which electrical circuit

Calculate the Reactance in given circuit

Calculate the susceptance (S) in given circuit

The plot of inductive reactance & frequency of source is

 An LCR circuit is equivalent to a damped pendulum. In an LCR circuit, the capacitor is charged to Q0 and then connected to the L and R as shown below :

If a student plots graphs of the square of maximum charge ( Q2Max ) on the capacitor with time(t) for two different values L1 and L2 (L 1>L2) of L then which of the following represents this graph correctly? (plots are schematic and not drawn to scale)

 

The power factor of an AC circuit having resistance (R) and inductance (L) connected in series and an angular velocity ω is :

An inductor of 10 mH is connected to a 20 V battery through a resistor of 10kΩ and a switch. After a long time, when maximum current is set up in the circuit, the current is switched off. The current in the circuit after 1μ s is x100 mA. Then x is equal to - (Take e1=0.37 )

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The phase difference between the alternating current and emf is \pi /2. Which of the following cannot be the constituent of the circuit?

 A series LR circuit is connected to a voltage source with  V(t)=V0sinωt. After a very long time, current I(t) behaves as (t0LR):


 

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In which of the following electrical circuit leading quantity is voltage

Concepts Covered - 1

Series LR circuit

Series LR circuit-

                                               

The above figure shows that pure inductor of inductance L connected in series with a resistor of resistance R through sinusoidal voltage, which is given by - V=V0sin(ωt+φ).

The alternating current I , which is flowing in the circuit gives rise to voltage drop VR across the resistor and voltage drop VL across the coil. As we have studied in previous concept that the voltage drop VR across R would be in phase with current but voltage drop across the inductor will lead the current by a phase factor π/2.

So, the voltage drop across R is VR=IR
voltage drop across the inductor L is - VL=I(ωL)
Where, I is the value of current in the circuit at a given instant of time
So, the voltage phasor diagram is -

                                                        

In the above figure, we have taken current as a reference quantity because same amount of current flows through both the components. Thus from phasor diagram - 

                                                       

V=VR2+VL2=IR2+ω2L2=IZ

where,

Z=(R2+ω2L2)1/2


Here, Z is known as Impedance of the circuit.

By using the formula of impedance we can write that -

I=V0sin(ωtϕ)Z


This is current in steady state which lags behind applied voltage by an angle φ.
From here and the above figure, we can write that -

tanφ=ωLR=XLR
 

 

Important term - 

1. Power factor - 

             

cosϕ=RZR resistance Z impedence 

2. Inductive susceptance ( SL ) -

It is the reciprocal of reactance.

SL=1XL=12πνL
 

 

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Series LR circuit

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