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Relative Velocity is considered one of the most asked concept.
32 Questions around this concept.
A man ( mass=50 kg ) and his son ( mass=20 kg) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of $0.70 \mathrm{~ms}^{-1}$ with respect to the man. The speed of the man (in $\mathrm{m} / \mathrm{s}$ ) with respect to the surface is :
$A$ person $A$ is moving along east and $B$ is moving along north. Then relative velocity of $A$ with respect to $B$ is $\left(V_A=10 \mathrm{~m} / \mathrm{s}, V_B=10 \sqrt{3} \mathrm{~m} / \mathrm{s}\right)$
A butterfly is flying with a velocity $4 \sqrt{2}$ in North-East direction. Wind is slowly blowing at $1 \mathrm{~m} / \mathrm{s}$ from North to South. The resultant displacement of the butterfly in 3 seconds is :
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A particle of mass m is at rest at the origin at time $\mathrm{t}=0$. It is subjected to a force $F(t)=F_0 e^{-b t}$ in the x direction Its speed $v(t)$ is depicted by which of the following curves ?
A container is kept in a moving bus.
The output, in the following gate logic, would be:
A police jeep chased a thief at , while thief traveled at . The police fired a bullet with an initial speed of . The speed at which it hits the thief’s car is:
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A moves with the speed of 50m/s ans B moves with 35m/s in same direction. The relative velocity of A w.r.t B is:
A train is moving with a velocity of 30m/s and the bus is moving behind it at a velocity of 10m/s in the same direction. The relative velocity of the bus with respect to the train is:
If $\overrightarrow{V_1}=5 \widehat{t i}+6 t^2 \widehat{j}$ and $\overrightarrow{V_2}=3 \widehat{i}+2 \widehat{t}$ then relative velocity of $\overrightarrow{V_1}$ with respect to $\overrightarrow{V_2}$ in time, $\mathrm{t}=1$ sec is :
Rate of change in position of one object with respect to another object with time is defined as relative velocity of one object with another.
Formula-
Relative velocity of object A with respect to object B .
$$
\vec{V}_{A B}=\vec{V}_A-\vec{V}_B
$$
- Relative velocity of $A$ with respect to $B$ is velocity of $A$ as observed by $B$.
- Case of Relative velocity
1. When $A$ and $B$ are moving along a straight line in the same direction.
$\overrightarrow{V_A}=$ Velocity of object $A$.
$\overrightarrow{V_B}=$ Velocity of object $B$.
Then, relative velocity of A w.r.t B is
$$
\begin{gathered}
\vec{V}_{A B}=\vec{V}_A-\vec{V}_B \\
\vec{V}_{A B}, \vec{V}_A, \vec{V}_B \text { all are in same direction. (If } \vec{V}_A>\vec{V}_{B)}
\end{gathered}
$$
And Relative velocity of $B$ w.r.t $A$ is
$$
\begin{aligned}
& \vec{V}_{B A}=\vec{V}_B-\vec{V}_A \\
& \& \vec{V}_{A B} \\
&=-\vec{V}_{B A}
\end{aligned}
$$
2. When A \& B are moving along with straight line in opposite direction.
Relative velocity of $A$ with respect to $B$ is.
$$
\begin{aligned}
& \vec{V}_{A B}=\vec{V}_A-\vec{V}_B \\
& V_{A B}=V_A+V_B
\end{aligned}
$$
3. Relative Velocity when bodies moving at an angle $\theta$ to each other
- Relative velocity of a body, A with respected body B
$$
V_{A B}=\sqrt{V_A^2+V_B^2+2 V_A V_B \cos (180-\theta)}
$$
$$
=\sqrt{V_A^2+V_B^2-2 V_A V_B \cos (\theta)}
$$
$V_A=$ velocity of $A$
$V_B=$ velocity of $B$
Where, $\theta=$ angle between $A$ and $B$
- If $\overrightarrow{V_{A B}}$ makes an angle $\beta$ with the direction of $\overrightarrow{V_A}$, then
$$
\begin{aligned}
& \tan \beta=\frac{V_B \sin (180-\theta)}{V_A+V_B \cos (180-\theta)} \\
& =\frac{V_B \cdot \sin \theta}{V_A-V_B \cos \theta}
\end{aligned}
$$
- If two bodies are moving at right angles to each other.
Relative Velocity of $A$ with respect to $B$ is
$$
V_{A B}=\sqrt{V_A^2+V_B^2}
$$
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