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Acceleration - Practice Questions & MCQ
Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
-
45 Questions around this concept.
Solve by difficulty
The displacement vs time graph is given below which of the following conclusions is correct?
Four velocity time graphs (Namely I , II , III , IV ) are shown in the figure. In which case is the acceleration uniform and positive
A car moving with 72 km/hr comes to rest in 5 second its acceleration is: (in m/s2)
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A particle is moving eastwards with a velocity of 5 m/s. In 10 s the velocity changes to 5 m/s northwards. The average acceleration in this time is
Match the following for the acceleration of a moving particle
P) Velocity increasing with time 1) zero
Q ) Velocity decreasing with time 2) positive
R )Velocity constant with time 3) Negative
A car starts from rest. Its velocity after 5 sec is 10 m/s then the average acceleration of the car is :
Direction: In the following question, a statement of Assertion (A) is followed by a statement of reason (R). Mark the correct choice as :
Assertion: A body can have acceleration even if its velocity is zero at a given instant in time
Reason: A body is momentarily at rest when it reverses its direction of motion
If the body is moving along the x-axis with an initial velocity equal to 2 m/s is accelerated to a final velocity of -6 m/s in 2 seconds. The average acceleration of the body is?
If x denotes displacement in x and x=a cost, then acceleration is :
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Use NowThe position, velocity and acceleration of a particle moving with constant acceleration can be represented by :
Concepts Covered - 1
Acceleration
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Definition: Rate of change of velocity with time.
$$
\vec{a}=\frac{\text { change in velocity }}{\text { time taken }}=\frac{\vec{v}_f-\vec{v}_i}{t}
$$- Tips for Acceleration-
1. The body is said to have undergone acceleration if there is a change in velocity i.e., :
- Change in speed
- Change in direction
- Change in both
2. It is a vector quantity
3. Dimension $=L T^{-2}$
4. S.I unit $=m \mathrm{~s}^{-2}$Example: A car starting from rest accelerates uniformly to a speed of $75 \mathrm{~m} / \mathrm{s}$ in 12 seconds. What is the car's acceleration?
Solution: $v_i=0$ (starting from rest)$$
v_f=75 \mathrm{~m} / \mathrm{s}
$$
From the definition of acceleration we know that,$$
\begin{aligned}
a & =\frac{v_f-v_i}{t} \\
& =\frac{75-0}{12}
\end{aligned}
$$
$$
\mathrm{a}=6.25 \mathrm{~m} / \mathrm{s}^2
$$
There are four types of acceleration
- Average acceleration- Total change in velocity per unit time taken is the average acceleration$$
\text { Avg. acceleration }\left(\vec{a}_{a v g}\right)=\frac{\Delta \vec{v}}{\Delta t}
$$- Instantaneous acceleration - Infinitesimal change in velocity per unit time taken is the average acceleration
$$
\text { Inst. acceleration }\left(\vec{a}_{\text {inst }}\right)=\frac{d \vec{v}}{d t}
$$
- Uniform acceleration- Change in velocity per unit time is constant.
- Non-uniform acceleration- Change in velocity per unit time is not constant. If the velocity and acceleration are directed in the opposite direction
- Slowing down or deceleration If the change in velocity is directed towards a negative direction (right to left) then acceleration is positive.
- Speeding up or acceleration If the change in velocity is directed towards a positive direction (left to right) then acceleration is positive.
- Negative Acceleration- Important terms related to acceleration.
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