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Equations of Linear Motion and Rotational Motion. is considered one of the most asked concept.
16 Questions around this concept.
A thin uniform rod of length and mass is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is . Its centre of mass rises to a maximum height of
A rod of length 50 cm is provided at one end. It is raised such that it makes an angle of $30^{\circ}$ from the horizontal as shown and released from rest. Its angular speed when it passes through the horizontal ( in rad s ${ }^{-1}$ ) will be ( $\mathrm{g}=10 \mathrm{~ms}^{-}$ $\left.{ }^2\right)$
A particle of mass $m$ moves along line PC with velocity $\nu$ as shown. What is the angular momentum of the particle about P?
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A particle of mass 2 kg is on a smooth horizontal table and moves in a circular path of radius 0.6 m. The height of the table from the ground is 0.8 m. If the angular speed of the particle is 12 rad s-1, the magnitude (in kg m2s-1) of its angular momentum about a point on the ground right under the centre of the circle is :
Linear Motion |
Rotational Motion |
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I |
If linear acceleration =a=0 Then u = constant and s = u t. |
If angular acceleration= Then w = constant and |
II |
If linear acceleration= a = constant 1. $a=\frac{v-u}{t}$ $$
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If angular acceleration=
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III |
If linear acceleration= a constant
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If angular acceleration $=\alpha \neq$ constant |
- Relation between linear and angular properties
1. $\vec{S}=\theta \overrightarrow{\times} \vec{r}$
2. $\vec{v}=\omega \overrightarrow{\times} \vec{r}$
3. $\vec{a}=\alpha \overrightarrow{\times} \vec{r}$
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