Relationship Between Linear And Angular Motion MCQ

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	Linear Motion	Rotational Motion
I	If linear acceleration =a=0 Then u = constant and s = u t.	If angular acceleration=$\alpha=0$ Then w = constant and $\theta=\omega \cdot t$
II	If linear acceleration= a = constant 1. $a=\frac{v-u}{t}$ 2. $v=u+a t$ 3. $s=u t+\frac{1}{2} a t^2$ 4. $s=\frac{v+u}{2} * t$ 5. $v^2-u^2=2 a s$ 6. $S_n=u+\frac{a}{2}(2 n-1)$	If angular acceleration=$\alpha=$ constant 1. $\alpha=\frac{\omega_f-\omega_i}{t}$ 2. $\omega_f=\omega_i+\alpha . t$ 3. $\theta=\omega_i \cdot t+\frac{1}{2} \cdot \alpha \cdot t^2$ 4. $\theta=\frac{\omega_f+\omega_i}{2} * t$ 5. $\omega_f^2-\omega_i^2=2 \alpha \theta$ 6. ${\theta_n}=\omega_i+\frac{\alpha}{2}(2 n-1)$
III	If linear acceleration= a $\neq$ constant 1. $v=\frac{d x}{d t}$ 2. $a=\frac{d v}{d t}=\frac{d^2 x}{d t^2}$ 3. $v . d v=a . d s$	If angular acceleration $=\alpha \neq$ constant 1. $\omega=\frac{d \theta}{d t}$ 2. $\alpha=\frac{d \omega}{d t}=\frac{d^2 \theta}{d t^2}$ 3. $\omega \cdot d \omega=\alpha \cdot d \theta$

Relationship Between Linear And Angular Motion - Practice Questions & MCQ