5 Questions around this concept.
Rain is falling vertically at a speed of 35 m/s. Wind started blowing after some time with a speed of 12 m/s in an east-to-west direction. In which direction should a boy waiting at a bus stop hold his umbrella with the vertical?
When a car is at rest, its driver sees raindrops falling on it vertically. When driving the car with speed $v$, he sees that raindrops are coming at an angle of $60^{\circ}$ from the horizontal. On further increasing the speed of the car to $(1+\beta) v$, this angle changes to $45^{\circ}$. The value of $100 \beta$ is close to :
A girl standing on a road hold her umbrella at $45^{\circ}$ with velocity to keep the rain away. If she starts running without umbrella with a speed of $15 \sqrt{2} \mathrm{kmh}^{-1}$, the rain drops hit her head vertically. The speed of rain drops with respect to the moving girl is $\mid$
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Terminology-
$
\begin{aligned}
& \overrightarrow{V_m}=\text { velocity of man in horizontal direction } \\
& \overrightarrow{V_r}=\text { velocity of rain w.r.t ground } \\
& \overrightarrow{V_{r m}}=\text { velocity of rain w.r.t man }
\end{aligned}
$
- Velocity of rain w.r.t man is given by
$
\overrightarrow{V_{r m}}=\overrightarrow{V_r}-\overrightarrow{V_m}
$
- For a Special case when Velocity of rain falling vertically
$
\text { Then, }{\tan \Theta}=\frac{V_m}{V_r}
$
Where $\Theta=$ angle which relative velocity of rain with
respect to man make with the vertical
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