Quality Factor In An AC Circuit - Practice Questions & MCQ

Quality factor-

The quality factor Q is a parameter which is used to describe the sharpness of resonance curve. So it is defined as the ratio of voltage drop across inductor or capacitor at resonance to the applied voltage. So,                                              

$
\begin{gathered}
Q=\frac{\text { Voltage across } L \text { or } C \text { at resonance }}{\text { Applied voltage }} \\
Q=\frac{I_v \omega_o L}{I_v R}=\omega_o \frac{L}{R}
\end{gathered}
$
As we know that, at the resonance -

$
\omega_o=\frac{1}{\sqrt{L C}}
$
So,

$
Q=\frac{1}{R} \sqrt{\frac{L}{C}}
$
 

We can also say that the characteristic of a series resonant circuit is determined by the quality factor (Q - factor) of the circuit. So, if the value of Q-factor is high then the sharpness of the resonant curve is more and vice-versa. 

We can also define the Q -factor that is is defined as  times the ratio of the energy stored in L or C to the average energy loss per period. So,

$
Q=2 \pi\left[\frac{\text { Maximum energy stored in the capacitor }}{\text { Energy loss per period }}\right]
$
Now, the maximum energy stored in the inductor =

$
U=\frac{1}{2} L\left(I_o\right)^2
$
Also the energy dissipated per second =

$
P_R=I_{r m s}^2 R=\frac{I_o^2 R}{2}
$
Energy dissipated per time period =

$
U_R=\frac{I_o^2 R}{2} \times T
$
Putting all these in the (1)

$
Q=\frac{1}{R} \sqrt{\frac{L}{C}}
$
 

voltage drop across inductance or capacitance is Q-times the applied voltage. 

From the graph we can see that when the Q-factor tends to infinity, then the current become infinite. And as the Q-factor become very low then the amplitude of the current will become very low.

In an ac circuit, If,
$R=0$ or $\cos \phi=0$

$
P_{a v}=0
$
Important term -
1. Wattless current

In resistance less circuit the power consumed is zero such circuit is called wattless and the current following is called wattless current.

Amplitude of wattless is $I_0 \sin \varphi$