JEE Main Deleted Syllabus 2025: Reduced Chapters & Topics PCM

Power Of Lens And Mirror - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Power of lens and mirror is considered one of the most asked concept.

  • 12 Questions around this concept.

Solve by difficulty

A person has been using spectacles of power $−1.0$ dioptre for distant vision and a separate reading glass of power $2.0$ dioptres. What is the least distance of distinct vision for this person :

A convex lens and a concave lens, each having the same focal length of \mathrm{25\ cm} are put in contact to form a combination of lenses. The power in diopters of the combination is:

Two lenses are placed in contact with each other and the focal length of the combination is \mathrm{80\ cm}. If the focal length of one is \mathrm{20\ cm}, then the power of the other will be:

An achromatic convergent doublet of two lenses in contact has a power of \mathrm{+ 2\ D}. The convex lens has power \mathrm{+ 5\ D}. What is the ratio of the dispersive powers of the convergent and divergent lenses?

The nearer point of the hypermetropic eye is \mathrm{40\ cm}. The lens to be used for its correction should have the power:

Concepts Covered - 1

Power of lens and mirror

Power and lens and mirror-

Power of a lens is defined as the reciprocal of focal length and Power of a mirror is defined as the negative of reciprocal of focal length.

                                                        So, 

                                                                P_{Lens}=\frac{1}{f} \ \ \ and \ \ \ P_{Mirror} = \frac{-1}{f}  

                                                                                  Where, f = focal length

The unit of power is Diopter, 1D = 1 m-1

The sign of the focal length will be taken according to the sign convention which we have discussed in the previous concept. 

The power of a combination of lenses in contact is the algebraic sum of the powers of individual lenses, so it can be written as -

                                                             P_{Total } = P_{I}+P_{2}+P_{3}+\dots+P_{n}

 

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Power of lens and mirror

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