EASYVIT - VITEEE 2025
ApplyNational level exam conducted by VIT University, Vellore | Ranked #11 by NIRF for Engg. | NAAC A++ Accredited | Last Date to Apply: 31st March | NO Further Extensions!
Power Of Lens And Mirror - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
-
Power of lens and mirror is considered one of the most asked concept.
-
19 Questions around this concept.
Solve by difficulty
Direction: In the following question, a statement of Assertion (A) is followed by a statement of reason (R). Mark the correct choice as:
Assertion: The power of a convex lens is positive and that of a concave lens is negative.
Reason: The power of lens is P =$\frac{1}{f}$
A biconcave lens of power P vertically splits into two identical plano concave parts. The power of each part will be
A biconvex lens of focal length f is cut into two identical plano convex lenses. The focal length of each part will be
JEE Main 2025: Admit Card Link | Study Plan | Official Question Paper (Session 1)
JEE Main 2025: Sample Papers | Mock Tests | PYQs | High Scoring Topics | College Predictor
New: Meet Careers360 experts in your city and get guidance on shortlisting colleges
Apply to TOP B.Tech /BE Entrance exams: VITEEE | MET | AEEE | BITSAT
Concepts Covered - 1
Power of lens and mirror
Power and lens and mirror-
Power of a lens is defined as the reciprocal of focal length and Power of a mirror is defined as the negative of reciprocal of focal length.
So,
So,
$
P_{\text {Lens }}=\frac{1}{f} \quad \text { and } \quad P_{\text {Mirror }}=\frac{-1}{f}
$
Where, $\mathrm{f}=$ focal length
The unit of power is Diopter, $1 \mathrm{D}=\mathbf{1} \mathbf{m}^{-1}$
The sign of the focal length will be taken according to the sign convention which we have discussed in the previous concept.
The power of a combination of lenses in contact is the algebraic sum of the powers of individual lenses, so it can be written as -
$
P_{\text {Total }}=P_I+P_2+P_3+\cdots+P_n
$
Study it with Videos
Power of lens and mirror"Stay in the loop. Receive exam news, study resources, and expert advice!"
Get Answer to all your questions
JEE Main Articles
Apr 01, 2025
Back to top