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Position of a point with respect to Hyperbola - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Position of a point with respect to Hyperbola is considered one of the most asked concept.

  • 8 Questions around this concept.

Solve by difficulty

Let $a$ and $b$ be the semi-transverse and semi-conjugate axes of a hyperbola whose eccentricity satisfies the equation $9 e^2-18 e+5=0$. If $S(5,0)$ is a focus and $5 x=9$ is the corresponding directrix of this hyperbola, then $\mathrm{a}^2-\mathrm{b}^2$ is equal to :

The foci of a hyperbola coincide with the foci of ellipse \mathrm{\frac{x^2}{25}+\frac{y^2}{9}=1}. If the eccentricity of the hyperbola is 3 , then its equation is

If the polar of a point w.r.t. \mathrm{\frac{x^2}{a^2}+\frac{y^2}{b^2}=1} touches the hyperbola \mathrm{\frac{x^2}{a^2}-\frac{y^2}{b^2}=1}, then the locus of the point is:

The locus of the poles of the chords of the hyperbola \mathrm{\frac{x^2}{a^2}-\frac{y^2}{b^2}=1}, which subtend a right angle at the centre is:

Concepts Covered - 1

Position of a point with respect to Hyperbola

Position of a point concerning Hyperbola

Let P(x1,y1) be any point in the plane

(a) P lies outside of the hyperbola : $\frac{\mathrm{x}_1{ }^2}{\mathrm{a}^2}-\frac{\mathrm{y}_1{ }^2}{\mathrm{~b}^2}-1<0$
(b) P lies on of the hyperbola $\quad: \frac{\mathrm{x}_1{ }^2}{\mathrm{a}^2}-\frac{\mathrm{y}_1{ }^2}{\mathrm{~b}^2}-1=0$
(c) P lies inside of the hyperbola : $\frac{\mathrm{x}_1{ }^2}{\mathrm{a}^2}-\frac{\mathrm{y}_1{ }^2}{\mathrm{~b}^2}-1>0$

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Position of a point with respect to Hyperbola

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