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Parallel and Perpendicular Lines - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Line parallel and perpendicular to a given line is considered one the most difficult concept.

  • 37 Questions around this concept.

Solve by difficulty

The locus of the mid-points of the perpendiculars drawn from points on the line,x=2y to the line x=y is :

If equation \mathrm{3 x-4 y=8\: and \: 2 p x+3 q y+12=0} represent the same lines then the values of \mathrm{p} and \mathrm{q} are:

Find the equation of line parallel to 2xy+1=0 and pass through (7,2).
 

 

 Find the equation of line perpendicular to x2y+3=0 and passing through (1,0)

The vertices of a triangle are A(-1,3), B(-2,2) and C(3,-1). A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is :

Find the value of d such that line (x+1)/5=(y+1)/2=(z+2)/1 lies on the plane x+y+z=d

A perpendicular line will be known if we are given 

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Concepts Covered - 1

Line parallel and perpendicular to a given line

Line parallel and perpendicular to a given line

1. The equation of the line parallel to ax+by+c=0 is given as ax+by+λ=0, where λ is some constant.

Equation of the given line is ax+by+c=0
Its slope is (a/b)
So, any equation of line parallel to ax+by+c=0 is

y=(ab)x+c1ax+bybc1=0ax+by+λ=0

2. The equation of the line perpendicular to ax+by+c=0 is given as bxay+λ=0, where λ is some constant.

Equation of the given line is ax+by+c=0
Its slope is (a/b)
Slope of perpendicular line will be (b/a)
So, any equation of line perpendicular to ax+by+c=0 is

y=(ba)x+c1bxbyac1=0bxay+λ=0
 

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Line parallel and perpendicular to a given line

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Line parallel and perpendicular to a given line

Mathematics for Joint Entrance Examination JEE (Advanced) : Coordinate Geometry

Page No. : 2.15

Line :

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