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Mayer's Formula - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Mayer's formula is considered one the most difficult concept.

  • 30 Questions around this concept.

Solve by difficulty

An ideal gas has molecules with 5 degrees of freedom.  The ratio of specific heat at constant pressure ( C_p) and at constant volume ( C_v) is :

According to the law of equipartition of energy, the molar specific heat of a diatomic gas at a constant volume where the molecule has one additional vibrational mode is

The correct relation between \mathrm{\gamma =\frac{c_{p}}{c_{v}}}  and temperature \mathrm{T}  is :

Concepts Covered - 1

Mayer's formula
  • Mayer's formula- As we know 

Molar Specific heat of the gas at constant volume=C_v

and  Molar Specific heat capacity at constant pressure=C_p

Mayer’s formula gives the relation between C_p and C_v as C_{p}= C_{v}+R 

or we can say that molar Mayer’s formula shows that specific heat at constant pressure is greater than that at constant volume.

  • Specific Heat in Terms of Degree of Freedom

1.Molar Specific heat of the gas at constant volume (C_v)

For a gas at temperature T, the internal energy

U=\frac{f}{2} n R T \Rightarrow \text { Change in energy } \Delta U=\frac{f}{2} n R \Delta T \ldots(\mathrm{i})

Also, as we know for any gas heat supplied at constant volume

(\Delta Q)_{V}=n C_{V} \Delta T=\Delta U.......(ii)  

From the equation (i) and (ii)

C_{v}= \frac{fR}{2}

where 

f = degree of freedom

R= Universal gas constant

2. Molar Specific heat of the gas at constant pressure (C_p)

From Mayer’s formula, we know that C_{p}= C_{v}+R

  \Rightarrow C_{P}=C_{V}+R=\frac{f}{2} R+R=\left(\frac{f}{2}+1\right) R

3. Atomicity or adiabatic coefficient (\gamma)

It is the ratio of C_p to C_v

\gamma =\frac{ C_{p}}{ C_{v}} =1+\frac{2}{f}

Value of \gamma is always more than 1

for Monoatomic gas     \gamma= \frac{5}{3}

for Diatomic gas         \gamma= \frac{7}{5}

for Triatomic gas        \gamma= \frac{4}{3}

  •  Gaseous Mixture

If two non-reactive gases A and B are enclosed in a vessel of volume V.

 In the mixture n1 mole of Gas A (having Specific capacities as C_p_1 and C_v_1 , Degree of freedom f_1 and Molar mass as M_1) is mixed with 

n2 mole of Gas B (having Specific capacities as C_p_2 and C_v_2 ,Degree of freedom f_2 and Molar mass as M_2)

Then Specific heat of the mixture at constant volume will be

C_{v_{mi x}}=\frac{n_{1} C_{v_{1}}+n_{2} C_{v_{2}}}{n_{1}+n_{2}}

Similarly, Specific heat of the mixture at constant pressure will be

C_{p_{mi x}}=\frac{n_{1} C_{p_{1}}+n_{2} C_{p_{2}}}{n_{1}+n_{2}}

And adiabatic coefficient (\gamma) of the mixture is given by

\gamma_{\text {mixure }}=\frac{C_{p_{m i x}}}{C_{v_{m x}}}=\frac{\frac{\left(n_{1} C_{p_{1}}+n_{2} C_{p_{2}}\right)}{n_{1}+n_{2}}}{\frac{\left(n_{1} C_{v_{1}}+n_{2} C_{v_{2}}\right)}{n_{1}+n_{2}}}=\frac{\left(n_{1} C_{p_{1}}+n_{2} C_{p_{2}}\right)}{\left(n_{1} C_{v_{1}}+n_{2} C_{v_{2}}\right)}

Also

\frac{1}{\gamma _{mix}-1}= \frac{\frac{n_1}{\gamma _{1}-1}+\frac{n_2}{\gamma _{2}-1}}{n_1+n_2}

Similarly, the Degree of freedom of mixture is given as

f_{mix}=\frac{n_1f_1+n_2f_2}{n_1+n_2}

Similarly, the molar mass of the mixture

M_{mix}=\frac{n_1M_1+n_2M_2}{n_1+n_2}

 

 

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Mayer's formula

Physics Part II Textbook for Class XI

Page No. : 329

Line : 4

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