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5 Questions around this concept.
The number of 3 digit numbers, that are divisible by either 3 or 4 but not divisible by 48, is
find the sum of the 37th bracket of the following series
$
\left.(1)+\left(7+7^2\right)+7^3\right)+\left(7^4\right)+7^5+7^6+7^7+7^8+\left(7^9\right)+7^{10}+----+7^{15} .
$
Let $C_0$ be a circle of radius 1 . For $n \geq 1$, let $C_n$ be a circle whose area equals the area of a square inscribed in $C_{n-1}$. Then $\sum_{i=0}^{\infty} \operatorname{Area}\left(C_i\right) \quad$ equals
If the differences of successive terms of a series are in AP
If the differences of successive terms of a series are in A.P., we can find the $\mathrm{n}^{\text {th }}$ term of the series by the following steps :
Step 1- Denote the $n^{\text {th }}$ term by $T_n$ and the sum of the series up to $n$ terms by $S_n$.
Step 2- Rewrite the given series with each term shifted by one place to the right.
Step 3- Now, subtract the second expression of $S_n$ from the first expression to obtain the general term $\mathrm{T}_{\mathrm{n}}$
After getting the nth term, we can get the sum by applying summation to it.
If the differences of successive terms of a series are in G.P
If the differences of successive terms of a series are in G.P., we can find the $\mathrm{n}^{\text {th }}$ term of the series by the following steps :
Step 1- Denote the $n$th term by $T_n$ and the sum of the series up to $n$ terms by $S_n$.
Step 2- Rewrite the given series with each term shifted by one place to the right.
Step 3- Now, subtract the second expression of $S_n$ from the first expression to obtain the general term $T_n$
After getting the general term $T_n$ applies summation on it to get a sum of n terms.
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