1 Questions around this concept.

- Let the separation between $\mathrm{S}_1$ and $\mathrm{S}_2$ be d and the distance of slits and the screen from the biprism be a and b respectively i.e. $D=(a+b)$. If the angle of the prism is $A$ and the refractive index is $\mu_{\text {then }} d=2 a(\mu-1) A$
$
\therefore \quad \lambda=\frac{\beta[2 a(\mu-1) A]}{(a+b)} \Rightarrow \beta=\frac{(a+b) \lambda}{2 a(\mu-1) A}
$
"Stay in the loop. Receive exam news, study resources, and expert advice!"
Errorless Physics Vol 2
Page No. : 1678
Line : 35
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Last Date to Apply: 18th May | Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
NAAC A+ Accredited | Among top 2% Universities Globally (QS World University Rankings 2026)
NAAC A++ Grade | Highest Package-30 LPA | 400+ Recruiters
NAAC A++ Grade | Recognized as Category-1 Deemed to be University by UGC | 41,000 + Alumni Imprints Globally
Explore on Careers360
Student Community: Where Questions Find Answers