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Formation of Differential Equation and Solutions of a Differential Equation is considered one of the most asked concept.
26 Questions around this concept.
The differential equation for the family of curves where is an arbitrary constant is.
The differential equation which represents the family of curves $y= c_{1}e^{c_{2}x},$ where $c_{1}\: and\: c_{2}$ are arbitrary constants, is
If the differential equation representing the family of all circles touching $x$-axis at the origin is $\left(x^2-y^2\right) \frac{d y}{d x}=g(x) y$, then $g(x)$ equals :
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The differential equation whose solution is are arbitrary constant, is of
The differential equation of all circles passing through the origin and having their centres on the -axis is.
The differential equation of the family of circles with fixed radius 5 units and centre on the line is
The degree and order of the differential equation of the family of all parabolas whose axis is -axis, are respectively.
The solution of the equation .
Formation of Differential Equation
We have studied the general formula of the parabola which is $y^2=4 a x$
This equation represents a family of parabolas with an arbitrary constant. With different values, we get a different parabola in this family.
To form its D.E, let us first differentiate it w.r.t. x,
$
2 \mathrm{y} \frac{\mathrm{dy}}{\mathrm{dx}}=4 \mathrm{a} \quad \text { or } \quad \frac{\mathrm{y}}{2} \frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{a}
$
Putting this value of 'a' in the original equation of a parabola
$
\begin{aligned}
& y^2=4 \cdot \frac{y}{2} \frac{d y}{d x} \cdot x \\
& 2 x \frac{d y}{d x}=y
\end{aligned}
$
This is the Differential Equation for a family of parabolas $y^2=4 a x$
Note that there is one arbitrary constant in the original equation, and the order of the D.E. formed is also 1. This is an important result: if an equation contains n arbitrary constants, then its D.E. will have an order equal to n.
If we are given a relation between the variables x, y with n arbitrary constants C1, C2, .... Cn, then to form its D.E., we differentiate the given relation n times in succession with respect to x, we have n + 1 equations altogether. Now using these we eliminate the n arbitrary constants. The result is a differential equation of the nth order.
Consider the equation of the family of ellipses with a and b as arbitrary constants
$
\frac{x^2}{a^2}+\frac{y^2}{b^2}=1
$
Differentiate Eq (4) w.r.t. ' $x$ '
$
\frac{2 \mathrm{x}}{\mathrm{a}^2}+\frac{2 \mathrm{y}}{\mathrm{~b}^2} \cdot\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)=0 \quad \text { or } \quad-\frac{\mathrm{b}^2}{\mathrm{a}^2}=\frac{\mathrm{yy}^{\prime}}{\mathrm{x}}
$
Differentiate above equation w.r.t. 'x'
$
\begin{gathered}
0=\frac{\mathrm{x}\left(\mathrm{y}^{\prime 2}+\mathrm{yy}^{\prime \prime}\right)-\mathrm{yy}^{\prime}}{\mathrm{x}^2} \\
\mathrm{yy}^{\prime}=\mathrm{xyy}^{\prime \prime}+\mathrm{x}\left(\mathrm{y}^{\prime}\right)^2
\end{gathered}
$
This is the D.E. that represents the given family of ellipses
Note: If arbitrary constants appear in addition, subtraction, multiplication, or division, then we can club them to reduce into one new arbitrary constant. Hence, the differential equation corresponding to a family of curves will have the order exactly same as a number of essential arbitrary constants (number of arbitrary constants in the modified form) in the equation of the curve.
Illustration :
Differential equation of the equation $\mathrm{y}=(\mathrm{a}+\mathrm{b}) \mathrm{e}^{\mathrm{x}}+\mathrm{e}^{\mathrm{x}+\mathrm{c}}$ is Here, the number of the arbitrary constant is $3: a, b, a n d$. But we can club arbitrary constants together
$
\mathrm{y}=\left(\mathrm{a}+\mathrm{b}+\mathrm{e}^{\mathrm{c}}\right) \mathrm{e}^{\mathrm{x}}
$
which is of the form, $\mathrm{y}=\mathrm{Ae}^{\mathrm{x}} \quad$ where, $\mathrm{A}=\left(\mathrm{a}+\mathrm{b}+\mathrm{e}^{\mathrm{c}}\right)$ hence, corresponding Differential equation will be of order 1
$
\begin{aligned}
& \Rightarrow \frac{d y}{d x}=A e^x \\
& \Rightarrow \frac{d y}{d x}=y
\end{aligned}
$
Solution of D.E.
If the given D.E. is
$
\begin{aligned}
& 2 x \frac{d y}{d x}=y \\
& 2 \frac{d y}{y}=\frac{d x}{x} \\
& 2 \int \frac{d y}{y}=\int \frac{d x}{x} \\
& 2 \ln (y)=\ln (x)+c
\end{aligned}
$
As c is a constant of integration, so it can take any real value. We can write it as $\ln (4 \mathrm{a})$ as well, where a is now the arbitrary constant.
$
\begin{aligned}
& \ln \left(y^2\right)=\ln (x)+\ln (4 a) \\
& y^2=4 a x
\end{aligned}
$
This is the general solution of the differential equation, which represents the family of the parabola
If we put some real value of an in this equation, then we get a particular solution of the given differential equation. For example,$\mathrm{a}=2$, then $\mathrm{y}^2=8 \mathrm{x}$ is a particular solution of this equation.
Hence, the solution of the differential equation is a relation between the variables of the equation that satisfy the D.E. and does not contain any derivatives or any arbitrary constants.
A general solution of a differential equation is a relation between the variables (not involving the derivatives) which contains the same number of the arbitrary constants as the order of the differential equation.
A particular solution of the differential equation is obtained from the general solution by assigning particular values to the arbitrary constant in the general solution.
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