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    Family of Circles - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Family of Circles is considered one of the most asked concept.

    • 95 Questions around this concept.

    Solve by difficulty

    If $\mathrm{y}=2 x$ is a chord of the circle $x^2+y^2=10 x$, then the equation of the circle whose diameter is this chord is

    The circles $x^2+y^2+2 x-2 y+1=0$ and $x^2+y^2-2 x-2 y+1=0$ touch each other

    The equation of a circle which passes through the point (1,-2) and (4,-3) and whose centre lies on the line 3x+4y=7 is 

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    Concepts Covered - 1

    Family of Circles

    Family of Circles

    1. Equation of the family of circles passing through the point of intersection of two given circles $S=0$ and $S^{\prime}=0$ is $S+\lambda S^{\prime}=0$ where $\lambda$ is the parameter

    2. Equation of the family of circles passing through the point of intersection of a given circle $S=0$ and a line $L=0$ is $S+\lambda L=0$ where $\lambda$ is the parameter.

    3. Equation of the family of circles touching the given circle $S=0$ and the line $L=0$ is $S+\lambda L=0$

    4. The equation of the family of circles passing through the two given points $P\left(x_1, y_1\right)$ and $Q\left(x_2, y_2\right)$ is

    $
    \left(\mathrm{x}-\mathrm{x}_1\right)\left(\mathrm{x}-\mathrm{x}_2\right)+\left(\mathrm{y}-\mathrm{y}_1\right)\left(\mathrm{y}-\mathrm{y}_2\right)+\lambda\left|\begin{array}{lll}
    x & y & 1 \\
    x_1 & y_1 & 1 \\
    x_2 & y_2 & 1
    \end{array}\right|=0
    $

    5. The equation of the family of circles which touch $\mathrm{y}-\mathrm{y}_1=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_1\right)$ at $\left(\mathrm{x}_1, \mathrm{y}_1\right)_{\text {for any finite }} \mathrm{m}$ is $\left(\mathrm{x}-\mathrm{x}_1\right)^2+\left(\mathrm{y}-\mathrm{y}_1\right)^2+\lambda\left\{\left(\mathrm{y}-\mathrm{y}_1\right)-\mathrm{m}\left(\mathrm{x}-\mathrm{x}_1\right)\right\}=0$ And if m is infinite then the family of circles is $\left(\mathrm{x}-\mathrm{x}_1\right)^2+\left(\mathrm{y}-\mathrm{y}_1\right)^2+\lambda\left(\mathrm{x}-\mathrm{x}_1\right)=0$

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    Family of Circles

    Mathematics for Joint Entrance Examination JEE (Advanced) : Coordinate Geometry

    Page No. : 4.33

    Line : 52

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