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18 Questions around this concept.
Let be the plane passing through the points (5, 3, 0), (13, 3, -2), and (1, 6, 2). For , if the distances of the points from the plane are 2 and 3 respectively, then the positive value of a is:
Let A, B and C be three non-collinear points on the plane with position vectors and respectively.
The vectors, and are in the given plane. Therefore, the vector is perpendicular to the plane containing points A, B and C.
Let P be any point in the plane with position vector .
Therefore, the equation of the plane passing through OP and perpendicular to the vector is
This is the equation of the plane in vector form passing through three noncollinear points.
Cartesian Form
Let (x1, y1, z1), (x2, y2, z2) and (x3, y3, z3) be the coordinates of points A, B and C respectively.
Let P(x, y, z) be any point on the plane.
Then, the vectors and are coplanar.
Intercept form of the equation of a plane
Cartesian Form
The equation of a plane having intercepting lengths a, b and c with X-axis, Y-axis and Z-axis, respectively is
Let the plane meets X, Y and Z-axes at (a, 0, 0), (0, b, 0), (0, 0, c) respectively and P(x, y, z) be any point on the plane.
Since these three points are non-collinear points.
Then, the vectors and are coplanar. where P be any point in the plane ABC.
This is the equation of the plane in cartesian form when the plane makes Intercepts a, b and c on the coordinate axes.
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