Amity University, Mumbai B.Tech Admissions 2025
ApplyRanked amongst top 3% universities globally (QS Rankings)
Equation of a plane perpendicular to a given vector and passing through a given point is considered one of the most asked concept.
25 Questions around this concept.
A plane bisects the line segment joining the points (1, 2, 3) and (−3, 4, 5) at right angles. Then this plane also passes through the point :
Find the foot perpendicular from the point
Imagine a pair of orthogonal vectors that share an initial point. Visualize grabbing one of the vectors and twisting it. As you twist, the other vector spins around and sweeps out a plane. Here, we describe that concept mathematically.
Let
We say that
If position vector of point
This is the vector equation of the plane.
Cartesian form
Position vector of point P and point Q is
Then,
Thus, the coefficients of x, y, and z in the cartesian equation of a plane are the direction ratios of the normal to the plane.
"Stay in the loop. Receive exam news, study resources, and expert advice!"
Mathematics for Joint Entrance Examination JEE (Advanced) : Vectors and 3D Geometry
Page No. : 4.28
Line : 6
188+ Downloads
34+ Downloads
4313+ Downloads
Ranked amongst top 3% universities globally (QS Rankings)
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 18th May
100% Placement Record | Highest CTC 54 LPA | NAAC A++ Accredited | Ranked #65 in India by NIRF Ranking 2024 | JEE & JET Scores Accepted
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
NAAC A++ Grade | Category-I Deemed to be University Grade by UGC
1000+ Recruiters | 450+ Patents | 50000+ Alumni network
Student Community: Where Questions Find Answers