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JEE Main Chapter wise Weightage 2025 for Physics, Chemistry, and Mathematics

Angle Between Two PlanesAngle Between Two Planes - Planes & Angles - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

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  • 11 Questions around this concept.

Concepts Covered - 1

Angle Between Two Planes

The angle between two planes is defined as the angle between their normals.

Let Ө be the angle between two planes \vec{\mathbf r}\cdot \vec{\mathbf n}_1=\mathbf d_1 and \vec{\mathbf r}\cdot \vec{\mathbf n}_2=\mathbf d_2 then,

\cos\theta=\frac{\vec{\mathbf n}_1\cdot \vec{\mathbf n}_2}{\left | \vec{\mathbf n}_1 \right |\left | \vec{\mathbf n}_1 \right |}

 

Condition for Perpendicularity of Two Plane

If the planes \vec{\mathbf r}\cdot \vec{\mathbf n}_1=\mathbf d_1 and \vec{\mathbf r}\cdot \vec{\mathbf n}_2=\mathbf d_2 are perpendicular, then \vec{\mathbf n}_1 and \vec{\mathbf n}_2 are perpendicular.

Therefore \vec{\mathbf n}_1 \cdot \vec{\mathbf n}_2 = 0.

 

Condition for Parallelism of Two Plane

If the planes \vec{\mathbf r}\cdot \vec{\mathbf n}_1=\mathbf d_1 and \vec{\mathbf r}\cdot \vec{\mathbf n}_2=\mathbf d_2 are parallel, then there exists a scalar λ such that  \vec{\mathbf n}_1 =\lambda \vec{\mathbf n}_2.

 

Cartesian Form

Let θ be the angle between the planes, a1x + b1y + c1z + d1 = 0 and a2x + b2y + c2z + d2 = 0 .

Then,

\cos \theta=\left|\frac{a_{1} a_{2}+b_{1} b_{2}+c_{1} c_{2}}{\sqrt{a_{1}^{2}+b_{1}^{2}+c_{1}^{2}} \sqrt{a_{2}^{2}+b_{2}^{2}+c_{2}^{2}}}\right|

The direction ratios of the normal to the planes are a1, b1, c1  and a2, b2 c2 respectively.
 

Condition for Perpendicularity of Two Planes

If the planes are at right angles, then θ = 90o and so cos θ = 0. Hence, cos θ = a1a2 + b1b2 + c1c2 = 0.
 

Condition for Parallelism of Two Plane

If the planes are parallel, then \frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}

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Angle Between Two Planes

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