Director Circle of Ellipse - Practice Questions & MCQ

Director Circle 

The equation of the director circle of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ is $\mathrm{x}^2+\mathrm{y}^2=\mathrm{a}^2+\mathrm{b}^2$

The locus of the point through which perpendicular tangents are drawn to a given Ellipse S = 0 is a circle called the director circle of the ellipse S = 0.

Equation of tangent of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ in slope form is $y=m x+\sqrt{a^2 m^2+b^2}$ it passes through the point $(h, k)$

$
\begin{aligned}
& k=m h+\sqrt{a^2 m^2+b^2} \\
& (k-m h)^2=a^2 m^2+b^2 \\
& k^2+m^2 h^2-2 m h k=a^2 m^2+b^2 \\
& \left(h^2-a^2\right) m^2-2 h k m+k^2-b^2=0
\end{aligned}
$
This is quadratic equation in $m$, slope of two tangents are $\mathrm{m}_1$ and $\mathrm{m}_2$

$
\begin{aligned}
& \mathrm{m}_1 \mathrm{~m}_2=\frac{\mathrm{k}^2-\mathrm{b}^2}{\mathrm{~h}^2-\mathrm{a}^2} \\
& -1=\frac{\mathrm{k}^2-\mathrm{b}^2}{\mathrm{~h}^2-\mathrm{a}^2} \quad[\text { tangents are prpendicular }] \\
& -\mathrm{h}^2+\mathrm{a}^2=\mathrm{k}^2-\mathrm{b}^2 \\
& \mathrm{x}^2+\mathrm{y}^2=\mathrm{a}^2+\mathrm{b}^2
\end{aligned}
$